Question

Bert didn't finish 1/8 of the problems on a math test he made Mistakes on 1/6 of the problems the rest he answered correctly what fraction of the problems did he answer correctly

Answer 1

Answer:

The fraction of the problems did he answer correctly is $(\frac{35}{48})$

Step-by-step explanation:

Here, let us assume the total number of problems in the test = p

Now, Bert did not finish 1/8 of the problems.

⇒The number of unfinished problems by Bert  = $\frac{1}{8} \times p= \frac{p}{8}$

Also, the number of finished problems  

=  Total problems - Unfinished problems

$= p - \frac{p}{8} = \frac{7p}{8}$

Now, again 1/6 of the total finished problems had mistakes.

So, the number of problems with mistakes = $\frac{1}{6} \times \frac{7p}{8} = \frac{7p}{48}$

The total answers did correctly

= Total answers done - Problem with mistakes

$= \frac{7p}{8} - \frac{7p}{48} = \frac{(42 - 7)p}{48} = \frac{35}{48}p$

Hence, the fraction of the problems did he answer correctly is $(\frac{35}{48})$