3 years ago

Simplify m²n+3xy-nm²-yx

1 answer:

5 0

Answer:
2xy

Explanation:
m^2n+3xy-nm^2-yx
Rewrite nm^2 as m^2n
=m^2n+3xy-m^2n-yx
Rewrite yx as xy
=m^2n+3xy-m^2n-xy
=3xy-xy
=2xy

I hope this helps!

You might be interested in

I really need help so i need you to help me with my homework so I can bring it back on Friday and it is done so I can get a grad

Yuri [45]

So what's the homework?

8 0

3 years ago

How many times greater is 36 than 32?

SIZIF [17.4K]

36/32 = 1.125

36 is 1.125 times the size of 32, or 0.125 time greater than 32.

5 0

3 years ago

Whats the intrgral of <img src="https://tex.z-dn.net/?f=%20%5Cint%20%20%5Cfrac%7Bx%5E2%2Bx-3%7D%7B%28x%5E3%2Bx%5E2-4x-4%29%5E2%7

rosijanka [135]

$\displaystyle\int\frac{x^2+x-3}{(x^3+x^2-4x-4)^2}\,\mathrm dx$

Notice that $x^3+x^2-4x-4=x^2(x+1)-4(x+1)=(x-2)(x+2)(x+1)$ . Decompose the integrand into partial fractions:

$\dfrac{x^2+x-3}{(x-2)^2(x+2)^2(x+1)^2}$
$=\dfrac1{3(x+1)}-\dfrac{11}{32(x+2)}-\dfrac1{3(x+1)^2}-\dfrac1{16(x+2)^2}+\dfrac1{96(x-2)}+\dfrac1{48(x-2)^2}$

Integrating term-by-term, you get

$\displaystyle\int\frac{x^2+x-3}{(x^3+x^2-4x-4)^2}\,\mathrm dx$
$=-\dfrac1{48(x-2)}+\dfrac1{3(x+1)}+\dfrac1{16(x+2)}+\dfrac1{96}\ln|x-2|+\dfrac13\ln|x+1|-\dfrac{11}{32}\ln|x+2|+C$

5 0

4 years ago

Which system of linear inequalities is represented by

Juli2301 [7.4K]

Answer:

I think it is b

3 0

3 years ago

Please help me at 7,11,13

MAXImum [283]

Answer:

Step-by-step explanation:

6 0

3 years ago

Simplify m²n+3xy-nm²-yx​

Simplify m²n+3xy-nm²-yx