Well 746÷40=18.65 so would that be 18?
I think that you are mistaking the memory tool for something else
or a math book is trying to make math cute by calling them 'socatoa joe' and 'mr. pi' and such
anyway, SOH, CAH, TOA is the way to remember
Sine=oposite/hypotonuse
Cosine=adjacent/hypotonuse
Tangent=oposite/adjacent
(oposite side=side oposite the angle
adjacent is the side touching the angle that is not they hypotonuse
and of course the hypotonuse is the longest side aka, side oposite right angle)
Answer:
The distribution of scores on this final exam is left-skewed.
Step-by-step explanation:
We use the Pearson Mode Skewness to solve this question. It states that:
If the median is higher than the mean, the distribution is left-skewed.
If the median is lower than the mean, the distribution is right-skewed.
If the median is the same as the mean, the distribution is symmetric.
In this problem, we have that:
Median = 74
Mean = 70
Median higher than the mean
So the distribution of scores on this final exam is left-skewed.
Answer:
Step-by-step explanation:
Begin by squaring both sides to get rid of the radical. Doing that gives you:
Now use the Pythagorean identity that says
and make the replacement:
. Now move everything over to one side of the equals sign and set it equal to 0 so you can factor:
and then simplify to
Factor out the common cos(x) to get
and there you have your 2 trig equations:
cos(x) = 0 and 1 - cos(x) = 0
The first one is easy enough to solve. Look on the unit circle and see where, one time around, where the cos of an angle is equal to 0. That occurs at
The second equation simplifies to
cos(x) = 1
Again, look to the unit circle and find where the cos of an angle is equal to 1. That occurs at π only.
So, in the end, your 3 solutions are
