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Andreyy89
3 years ago
14

Find the equation of the line. Y=__x + __

Mathematics
2 answers:
kkurt [141]3 years ago
7 0
To find the slope (m), count how many units vertically and horizontally it takes to get from any one point to the other (rise/run)

i’ll use (0,-6) and (-4,-5)
it takes 1 vertical unit and 4 horizontal units to the left to get there, so the slope is 1/-4

to find the y intercept (b), it’s simply the point where the line intercepts the y axis (vertical line). in this case it’s at (0,-6). the y intercept would then be -6

now just plug those into the slope intercept form: y = mx + b

the equation of the line is y = 1/-4x - 6
mestny [16]3 years ago
7 0
Answer: y= -1/4x - 6
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If x equals 3 calculate the value of 2x squared plus x
Korolek [52]
2 × 3 = 6
6 squared = 36
36 + 3 = 39
Hope this helps!
6 0
3 years ago
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Fei Yen's dog eats 8 ounces of dog food each day.Fei Yen's bought a 28 pound bag of dog food.How many 8 ounce servings are in a
joja [24]

Answer:

56

Step-by-step explanation:

Recall that 1 lb = 16 oz, meaning that 1/2 lb = 8 oz.

Thus, we need only divide 28 lb by 1/2 lb to determine the number of 8 oz servings are contained in a 28 lb bag of dog food:

28 lb

--------------------- = 56 8-oz servings

1/2 lb/ serving

8 0
3 years ago
PLS HELP WILL MARK YOU BRAINLIEST! NO FAKE ANSWERS
bixtya [17]

Answer:

30%

Step-by-step explanation:

the first solution -30% will be 45% and the second solution added by 30% will be 45%

4 0
2 years ago
Read 2 more answers
What is the perimeter of this quadrilateral?<br> (5,5)<br> (2, 4)<br> (4, 1)<br> (6, 1)
lbvjy [14]

~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_1}{5}~,~\stackrel{y_1}{5})\qquad B(\stackrel{x_2}{2}~,~\stackrel{y_2}{4}) ~\hfill AB=\sqrt{[ 2- 5]^2 + [ 4- 5]^2} \\\\\\ AB=\sqrt{(-3)^2+(-1)^2}\implies \boxed{AB=\sqrt{10}} \\\\[-0.35em] ~\dotfill\\\\ B(\stackrel{x_1}{2}~,~\stackrel{y_1}{4})\qquad C(\stackrel{x_2}{4}~,~\stackrel{y_2}{1}) ~\hfill BC=\sqrt{[ 4- 2]^2 + [ 1- 4]^2}

BC=\sqrt{2^2+(-3)^2}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ C(\stackrel{x_1}{4}~,~\stackrel{y_1}{1})\qquad D(\stackrel{x_2}{6}~,~\stackrel{y_2}{1}) ~\hfill CD=\sqrt{[ 6- 4]^2 + [ 1- 1]^2} \\\\\\ CD=\sqrt{2^2+0^2}\implies \boxed{CD=2} \\\\[-0.35em] ~\dotfill\\\\ D(\stackrel{x_1}{6}~,~\stackrel{y_1}{1})\qquad A(\stackrel{x_2}{5}~,~\stackrel{y_2}{5}) ~\hfill DA=\sqrt{[ 5- 6]^2 + [ 5- 1]^2}

DA=\sqrt{(-1)^2+4^2}\implies \boxed{DA=\sqrt{17}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{\Large Perimeter}}{\sqrt{10}~~ + ~~\sqrt{13}~~ + ~~2~~ + ~~\sqrt{17}}~~ \approx ~~ 12.89

8 0
2 years ago
Help guys plzzz asapppp
nignag [31]

sin(x) = opp/hyp
cos(x) = adj/hyp
tan(x) = opp/adj

sin(x) = 3.9/8.1
sin(x) = 0.481

Inverse sin of 0.481 = 28.8 degrees

Each answer should be between 0 and 90 :)
4 0
2 years ago
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