Question

A. In the complete reaction of 22.99 g of sodium

Answer 1

Answer : 58.44 g

Further explanation

The reaction

$\tt Na+Cl\Rightarrow NaCl$

mole ratio :

Na : Cl : NaCl = 1 : 1 : 1

Molar mass of Na : 22,989769 g/mol = 22.99 g/mol

Molar mass of Cl : 35,453 g/mol= 35.45 g/mol

Molar mass of NaCl : 58,44 g/mol

Let's check the mol for reactant (Na and Cl) and product(NaCl)

• mol of Na :

$\tt mol=\dfrac{22.99}{22.99}=1$

• mol of Cl :

$\tt mol=\dfrac{35.45}{35.45}=1$

Then the reactants are completed reacting because it matches the mole ratio, which is 1: 1

so that the mole of the product can be determined from the mol Na or Cl, which is 1

• mass of NaCl :

$\tt =\dfrac{mol~NaCl}{mol~Na}\times MW~NaCl\\\\=\dfrac{1}{1}\times 58.44\\\\=\boxed{\bold{58.44~g}}$