The cost of each ribeye steak dinner is $ 29 and cost of each grilled salmon dinner is $ 20
<em><u>Solution:</u></em>
Let "a" be the cost of each ribeye steak dinners
Let "b" be the cost of each grilled salmon dinners
<em><u>A waitress sold 11 ribeye steak dinners and 12 grilled salmon dinners, totaling $560.63 on a particular day</u></em>
Thus we frame a equation as:
11 x cost of each ribeye steak dinners + 12 x cost of each grilled salmon dinners = 560.63
![11 \times a + 12 \times b = 560.63](https://tex.z-dn.net/?f=11%20%5Ctimes%20a%20%2B%2012%20%5Ctimes%20b%20%3D%20560.63)
11a + 12b = 560.63 -------- eqn 1
<em><u>Another day she sold 16 ribeye steak dinners and 6 grilled salmon dinners, totaling $584.46</u></em>
Thus we frame a equation as:
16 x cost of each ribeye steak dinners + 6 x cost of each grilled salmon dinners = 584.46
![16 \times a + 6 \times b = 584.46](https://tex.z-dn.net/?f=16%20%5Ctimes%20a%20%2B%206%20%5Ctimes%20b%20%3D%20584.46)
16a + 6b = 584.46 ------------ eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
<em><u>Multiply eqn 2 by 2</u></em>
32a + 12b = 1168.92 ------- eqn 3
<em><u>Subtract eqn 1 from eqn 3</u></em>
32a + 12b = 1168.92
11a + 12b = 560.63
( - ) ----------------
21a = 1168.92 - 560.63
21a = 608.29
Divide both sides by 21
![a = 28.96 \approx 29](https://tex.z-dn.net/?f=a%20%3D%2028.96%20%5Capprox%2029)
<em><u>Substitute a = 29 in eqn 1</u></em>
11(29) + 12b = 560.63
319 + 12b = 560.63
12b = 560.63 - 319
12b = 214.63
Divide both sides by 12
![b = 20.13 \approx 20](https://tex.z-dn.net/?f=b%20%3D%2020.13%20%5Capprox%2020)
Thus cost of each ribeye steak dinner is $ 29 and cost of each grilled salmon dinner is $ 20