You have to make a problem that could happen in the real world that multiplication of a fracton using product between 10 and 15
Answer:
We have been given a unit circle which is cut at k different points to produce k different arcs. Now we can see firstly that the sum of lengths of all k arks is equal to the circumference:

Now consider the largest arc to have length \small l . And we represent all the other arcs to be some constant times this length.
we get :

where C(i) is a constant coefficient obviously between 0 and 1.

All that I want to say by using this step is that after we choose the largest length (or any length for that matter) the other fractions appear according to the above summation constraint. [This step may even be avoided depending on how much precaution you wanna take when deriving a relation.]
So since there is no bias, and \small l may come out to be any value from [0 , 2π] with equal probability, the expected value is then defined as just the average value of all the samples.
We already know the sum so it is easy to compute the average :

The slope would represent the cost per minute, since m is the length of the call in minutes. Logically, D) Cost per minute, is the only one that would work. The connection cost would be just added in, and you wouldn't multiply the cost of having a phone line by how many minutes you're on the phone. The length of the call is already there, it's m, so that wouldn't work either. Therefore, D, cost per minute, is the logical answer. The slope in the equation represents D, cost per minute.
Answer:
<em>36:60:84</em>
<em>A : B : C</em>
<em>36° : 60° : 84°</em>
<em>A= 36°</em>
<em>B= 60°</em>
<em>C=84°</em>
Step-by-step explanation:
<em>3:5:7 =15</em>
<em>180÷15=12</em>
<em>3×12=36</em>
<em>36:x:y =180</em>
<em>5×12=60</em>
<em>36:60:y =180</em>
<em>7×12=84</em>
<em>36:60:84 =180</em>
I don’t know the answer but I need points sorry