<span>First note that y cannot equal -7 or -1 as division by zero is undefined. So that if it comes up in our solution we know that it is not a real solution.
[(y+4)/(y+7)]+1=(y+3)/(y+1) make the left side have a common denominator
(y+4+y+7)/(y+7)=(y+3)/(y+1) combine like terms on left side
(2y+11)/(y+7)=(y+3)/(y+1) cross multiply
(2y+11)(y+1)=(y+3)(y+7) expand
2y^2+13y+11=y^2+10y+21 subtract y^2 from both sides
y^2+13y+11=10y+21 subtract 10y from both sides
y^2+3y+11=21 subtract 21 from both sides
y^2+3y-10=0 expand so factoring is easier
y^2-2y+5y-10=0 factor
y(y-2)+5(y-2)=0 which is equal to
(y+5)(y-2)=0
y=-5 or 2</span>
Remark
Sometimes you can avoid the distributive property. This is one of those cases. Start by dividing by 5. You can only do this is there a common factor between the left and right sides of the equal sign.
Solve
There is only 1 solution. If there was an x^2 somewhere, you would have 2 and if there was an x^3 there would be 3.
5(2x - 3) = 5 Divide both sides by 5
5(2x - 3)/5 = 5/5
(2x - 3) = 1 Remove the brackets.
2x - 3 = 1 Add 3 to both sides.
2x = 1 + 3
2x = 4 Divide by 2
x = 4/2
x = 2 <<<<< Answer
Answer:
6 - pack of scented candles for $40.5?
Step-by-step explanation:
$30 ÷ 4 = $7.5 for one
$40.5 ÷ 6 = $6.75 for one
therefore 6 - pack of scented candles for $40.5 is more cheap.
Answer:
It would be 6
Step-by-step explanation: