Y-5=m(x-2) solve for x

What are the following of this function y = 4sin (2( x - <img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%5Cpi%20%7D%7B4%7D" id="Te

Andrei [34K]

Answer:

See below...

Step-by-step explanation:

For a function whose formula is in this pattern:

$y=A\sin\left(B(x-C)\right)$

Amplitude: $|A|$

Period: $\frac{2\pi}{B}$

Phase Shift: C

In this question, $A=4,\,B=2,\,C=\frac{3\pi}{4}$

Amplitude: 4

Period: $\frac{2\pi}{2}=\pi$

Phase Shift: $\frac{3\pi}{4}$

There is no vertical shift, so the midline is the x-axis whose equation is y = 0.

Also, because there is no vertical shift, the maximum is 4 and the minimum is -4.

The graph is attached.

6 0

3 years ago

What is the arc measure, in degrees, of minor arc AC on circle P below?

Gennadij [26K]

Answer: 174

For khan academy :)

5 0

4 years ago

Please answer this correctly

BabaBlast [244]

Answer:

19.63

Step-by-step explanation:

If the radius is 5 centimeters, then the area is just 3.14*5^2 / 4, which is 78.5/4. This is equal to 19.625. Rounding this give us 19.63 as the final answer

8 0

3 years ago

Place the indicated product in the proper location on the grid. (4x^3+7y^3 z^ 4) ^2

ella [17]

Answer:

$16x^{6} +56x^{3}y^{3} z^{4} +49y^{6} z^{8} \\$

Step-by-step explanation:

To solve this type of problems first need to review some laws of exponents:

When you are multiplying the same base, you need to add the exponents.

$x^{2} +x^{8} = x^{2+8} = x^{10}$

When you are raising a base with power to another power, you should keep the base and multiply the exponents:

$(x^{2} y^{5})^3 = x^{2*3} y^{5*3} = x^{6} y^{15}$

Now for the expression $(4x^{3} + 7y^{3} z^{4} )^2$

Write the multiplying factors:

$(4x^{3} + 7y^{3} z^{4} )(4x^{3} + 7y^{3} z^{4} )$

Multiply the term $4x^{3}$

$(4x^{3} + 7y^{3} z^{4} )(4x^{3} + 7y^{3} z^{4} ) = 16x^{3+3} + 28x^3y^{3} z^{4}$

Then multiply the term $7y^{3}z^{4}$

$(4x^{3} + 7y^{3} z^{4} )(4x^{3} + 7y^{3} z^{4} ) = 16x^{3+3} + 28x^3y^{3} z^{4}\\\\+ 28x^3y^{3} z^{4} + 49y^{3+3} z^{4+4}$

Simplify the exponents:

$(4x^{3} + 7y^{3} z^{4} )(4x^{3} + 7y^{3} z^{4} ) = 16x^{6} + 28x^3y^{3} z^{4}\\\\+ 28x^3y^{3} z^{4} + 49y^{6} z^{8}$

Add like terms:

$= 16x^{6} + 56x^3y^{3} z^{4} + 49y^{6} z^{8}$

5 0

3 years ago

Match the solution set given in inequality notation with the solution set given in interval notation.

sasho [114]

Answer:

x≤7.8 ⇒(-∞;7.8]

x<7.8 ⇒ (-∞;7.8)

x>7.8 ⇒ (7.8; ∞)

x≥7.8 ⇒ [7.8; ∞)

Step-by-step explanation:

Hi, to answer this question we have to analyze each expression:

• x≤7.8

The solution is all the numbers less or equal to 7.8, since it can be equal to 7.8, it includes 7.8 , we have to use closed brackets

(-∞;7.8]

• x<7.8

All the numbers less than 7.8 , it excludes the endpoint , it's an open interval (parenthesis)

(-∞;7.8)

• x>7.8

All the numbers higher than 7.8, open interval (parenthesis)

(7.8; ∞)

• x≥7.8

All the numbers higher or equal to 7.8, closed interval (closed brackets for the endpoint)

[7.8; ∞)

4 0

3 years ago