T = days passed
r = rate of growth
by 0 day, or t = 0, there are 2 folks sick,

by the third day, t = 3, there are 40 folks sick,
![\bf \qquad \textit{Amount for Exponential Growth} \\\\ A=P(1 + r)^t\qquad \begin{cases} A=\textit{accumulated amount}\to &40\\ P=\textit{initial amount}\to &2\\ r=rate\to r\%\to \frac{r}{100}\\ t=\textit{elapsed time}\to &3\\ \end{cases} \\\\\\ 40=2(1+r)^3\implies 20=(1+r)^3\implies \sqrt[3]{20}=1+r \\\\\\ \sqrt[3]{20}-1=r\implies 1.7\approx r\qquad \boxed{A=2(2.7)^t}](https://tex.z-dn.net/?f=%5Cbf%20%5Cqquad%20%5Ctextit%7BAmount%20for%20Exponential%20Growth%7D%0A%5C%5C%5C%5C%0AA%3DP%281%20%2B%20r%29%5Et%5Cqquad%20%0A%5Cbegin%7Bcases%7D%0AA%3D%5Ctextit%7Baccumulated%20amount%7D%5Cto%20%2640%5C%5C%0AP%3D%5Ctextit%7Binitial%20amount%7D%5Cto%20%262%5C%5C%0Ar%3Drate%5Cto%20r%5C%25%5Cto%20%5Cfrac%7Br%7D%7B100%7D%5C%5C%0At%3D%5Ctextit%7Belapsed%20time%7D%5Cto%20%263%5C%5C%0A%5Cend%7Bcases%7D%0A%5C%5C%5C%5C%5C%5C%0A40%3D2%281%2Br%29%5E3%5Cimplies%2020%3D%281%2Br%29%5E3%5Cimplies%20%5Csqrt%5B3%5D%7B20%7D%3D1%2Br%0A%5C%5C%5C%5C%5C%5C%0A%5Csqrt%5B3%5D%7B20%7D-1%3Dr%5Cimplies%201.7%5Capprox%20r%5Cqquad%20%5Cboxed%7BA%3D2%282.7%29%5Et%7D)
how many folks are there sick by t = 6?
Answer:
Option 2 50 ≤ s ≤ 100
Option 5 She could deposit $50
Option 6 She could deposit $75
Step-by-step explanation:
Let
s -----> amount of money Layla deposit into a saving account
we know that
25%=25/100=0.25
50%=50/100=0.50
so
-----> 
-----> 
The compound inequality is

<em>Verify each case</em>
case 1) 25 ≤ s ≤ 50
The statement is false
see the procedure
case 2) 50 ≤ s ≤ 100
<u>The statement is True</u>
see the procedure
case 3) s ≤ 25 or s ≥ 50
The statement is false
Because is s ≤ 100 and s ≥ 50
case 4) s ≤ 50 or s ≥ 100
The statement is false
Because is s ≤ 100 and s ≥ 50
case 5) She could deposit $50
<u>The statement is true</u>
Because the value of s satisfy the compound inequality 
case 6) She could deposit $75
<u>The statement is true</u>
Because the value of s satisfy the compound inequality 
Answer:
the area of the mat = total area added minus the original area of the water color painting.
length of the mat is:
L = 21 in + 3 in + 3 in because 3 in is added to each side
L = 27 inwidth of the mat is:w = 11 in + 3 in + 3 inw = 17in
Area mat = (27 in x 17 in) - ( 21 in x 27 in)
area mat = 108 sq in is the area of the mat
Answer:
y = 6
Step-by-step explanation:
If x varies inversely proportional as y.
, k is constant of proportionality
or
k = xy
When x = 3 and y = 10
k = 3×10
k = 30
Put x = 5,

So, the value of y is 6 when x is 5.