Please help me please

A market analyst is hired to provide information on the type of customers who shop at a particular store. A random survey is taken of 100 shoppers at this store. Of these 100, 73 are women. The shoppers The data is summarized below. we grouped in three age categories, under 30, 30 up to 50 and 50 and over. Women under 30 are 30, Men under 30 are 8 Women 30 to 50 are 25 and Men are 14 Women 50 and over are 18 and Men are 5.

Let W be the event that a randomly selected shopper is a woman. Let A be the event that a randomly selected shopper is under 30. a.) Find the probability of W. W (women Shoppers) = Find the probability of A. b.) Find the probability of A and W. c.) P (A and W) (Shoppers) d.) Find the probability of A or W. P(A or W) (Shoppers) e.) Find the probability of A given W

Answer:

A) P(W) = 73/100; B) P(A) = 38/ 100 C) 30 / 100

D) 81/100 E) 30/73

Step-by-step explanation:

- - - - - - - - Women Men Total

Under 30 - - - 30 - - - 8 - - 38

30 to 50 - - - - 25 - - 14 - - 39

50 & over - - - 18 - - - 5 - - -23

Totals - - - - - - 73 - - -27 - - 100

Recall:

Probability : P= (required outcome / Total possible outcomes)

A) probability of women shoppers: P(W)

Number of women shoppers = 73; total shoppers = 100

P(W) = 73/100

B) Probability of under 30: P(A)

= number of shoppers under 30 = 38

Tital number of shoppers = 100

P(A) = 38/ 100

C) probability of A and W; This is the probability that the selected person is a woman and under 30.

(W n A) = 30

= 30 / 100

D) probability of A or W:

P(A) + P(W) - P(A n W) :

(38 / 100 + 73 / 100 - 30 / 100) = (38+73-30) /100

= 81/100

E) probability of A given W:

P(A n W) / P(W) = 30/73

5 0

3 years ago

Can I get help solving this graph please?

Daniel [21]

see the attached figure with the letters

1) find m(x) in the interval A,B
A (0,100) B(50,40) -------------- > p=(y2-y1(/(x2-x1)=(40-100)/(50-0)=-6/5
m=px+b---------- > 100=(-6/5)*0 +b------------- > b=100
mAB=(-6/5)x+100

2) find m(x) in the interval B,C
B(50,40) C(100,100) -------------- > p=(y2-y1(/(x2-x1)=(100-40)/(100-50)=6/5
m=px+b---------- > 40=(6/5)*50 +b------------- > b=-20
mBC=(6/5)x-20

3) find n(x) in the interval A,B
A (0,0) B(50,60) -------------- > p=(y2-y1(/(x2-x1)=(60)/(50)=6/5
n=px+b---------- > 0=(6/5)*0 +b------------- > b=0
nAB=(6/5)x

4) find n(x) in the interval B,C
B(50,60) C(100,90) -------------- > p=(y2-y1(/(x2-x1)=(90-60)/(100-50)=3/5
n=px+b---------- > 60=(3/5)*50 +b------------- > b=30
nBC=(3/5)x+30

5) find h(x) = n(m(x)) in the interval A,B
mAB=(-6/5)x+100
nAB=(6/5)x
then
n(m(x))=(6/5)*[(-6/5)x+100]=(-36/25)x+120
h(x)=(-36/25)x+120
find <span>h'(x)
</span>h'(x)=-36/25=-1.44

6) find h(x) = n(m(x)) in the interval B,C
mBC=(6/5)x-20
nBC=(3/5)x+30
then
n(m(x))=(3/5)*[(6/5)x-20]+30 =(18/25)x-12+30=(18/25)x+18
h(x)=(18/25)x+18
find h'(x)
h'(x)=18/25=0.72

for the interval (A,B) h'(x)=-1.44
for the interval (B,C) h'(x)= 0.72

<span> h'(x) = 1.44 ------------ > not exist</span>

8 0

2 years ago

Taxi Driver charges a fixed rate of R to pick up a passenger in addition to Taxi Driver charges a rate of M for each mile driven

IRISSAK [1]

Answer:

t=nm+r

Step-by-step explanation:

Since you are trying to find time, represented by t, you set the equation equal to t. Then you need to add n multiplied by miles, m, to the fixed rate, r.

3 0

2 years ago