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3 years ago

Im stuck on this please help

Mathematics

1 answer:

kondaur [170]3 years ago

4 0

"For what value of x does g(x) = 0"

g(x) = y

This is asking:

when y = 0, what is the value of x?

Or you can see it as (?, 0)

6 is the value of x

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The area of a circle is 113.04 square meters. What is the circle's radius? (Using 3.14 as pi)

notka56 [123]

Answer:

Step-by-step explanation:

113,04=3,14×r²

113,04/3,14=r²

*√ both sides*

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3 years ago

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Four subtracted from the reciprocal of a number

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3 years ago

"Duela Dent is single and had $189,000 in taxable income. Using the rates from Table 2.3 in the chapter, calculate her income ta

lilavasa [31]

From the income provided, the taxable income will be $42170.

<h3>How to calculate the taxable income</h3>

From the complete information, the calculation goes thus

First $9525 = 10% = $952.50

Next $9525 - $38700 = 12% = $3501.00

Next $38700 - $82500 = 22% = $9636

Next $82500 - $157500 = 24% = $18000

Next $157500 - $189000 = $10080

Taxable Income = $952.50 + $3501.00 + $9636 + $18000 + $10080

= $42170

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brainly.com/question/2743145

7 0

2 years ago

2 3 x - 4 = -2 plss tell meee

lions [1.4K]

Assuming you meant 2/3x -4= -2 the answer would be x=3

8 0

3 years ago

A certain forest covers an area of

iVinArrow [24]

Answer:

2598 square kilometers

Step-by-step explanation:

Hello

Step 1

year one

using a rule of three is possible to find how much is 8.75 od 4500 km2

Let

4500 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$4500:100\\x:8.75\\\frac{4500}{100}=\frac{x}{8.75}\\x=\frac{4500*8.75}{100} \\x=393.75\\$

at the end of the year one, the area will be

4500-393.75=4106.25

this will be the initial area for the year 2.

Step 2

repite the step 1 with area initial =4106.25 km2

4106.25 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$4106.25:100\\x:8.75\\\frac{4106.25}{100}=\frac{x}{8.75}\\x=\frac{4106.25*8.75}{100} \\x=359.29\\$

at the end of the year 2, the area will be

4106-359.29=3746.70

this will be the initial area for the year 3.

Step 3

repite the step 1 with area initial =4106.25 km2

3746.70 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$3746.70:100\\x:8.75\\\frac{3746.70}{100}=\frac{x}{8.75}\\x=\frac{3746.7*8.75}{100} \\x=327.83\\$

at the end of the year 3, the area will be

3746.70-327.83=3419.09

this will be the initial area for the year 4.

Step 4

year four

repite the step 1 with area initial =3419.09 km2

3419.09 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$3419.09:100\\x:8.75\\\frac{3419.09}{100}=\frac{x}{8.75}\\x=\frac{3419.09*8.75}{100} \\x=299.17\\$

at the end of the year 4, the area will be

3419.09-299.173=3119.82

this will be the initial area for the year 5.

Step 5

year five

repite the step 1 with area initial =3119.82 km2

3119.82 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$3119.82:100\\x:8.75\\\frac{3119.82}{100}=\frac{x}{8.75}\\x=\frac{3119.82*8.75}{100} \\x=272.99\\$

at the end of the year 5, the area will be

3119.82-272.99=2846.92

this will be the initial area for the year 6.

Step 6

year six

repite the step 1 with area initial =2846.92km2

2846.92 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$2846.92:100\\x:8.75\\\frac{2846.92}{100}=\frac{x}{8.75}\\x=\frac{2846.92*8.75}{100} \\x=249.10\\$

at the end of the year six, the area will be

2846.92-249.10=2597.82 square kilometers

Have a great day.

8 0

3 years ago