Question

There are three consecutive even integers. If twice the first integer added to the second is 268,244, find all three integers.

Answer 1

Answer:

89414,89416,89418

Step-by-step explanation:

Let n bet the positive integer and then 2n is an even integer because multiplying n with 2 makes it an even integer.

Now, 2n+2, 2n+4 are the next integers.

Therefore, three consecutive integers are: 2n, 2n+2, 2n+4.

It is given that twice the first integer added to the second is 268,244 that means:

$2(2n)+(2n+2)=268244$

$4n+2n+2=268244$

$6n=268242$

$n=44707$

Therefore, three consecutive integers are:

2n=89414, 2n+2=89416, 2n+4=89418