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Viefleur [7K]
4 years ago
9

SinΘ = 15/17 and Θ lies in Q1, find cos 2Θ

Mathematics
1 answer:
Readme [11.4K]4 years ago
7 0
\cos^2\theta=1-\sin^2\theta
\cos^2\theta=1-\dfrac{225}{289}=\dfrac{64}{289}

\cos2\theta=\cos^2\theta-\sin^2\theta
\cos2\theta=\dfrac{64}{289}-\dfrac{225}{289}=-\dfrac{161}{289}
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