Answer:
- plane: 530 mi/h
- wind: 40 mi/h
Step-by-step explanation:
Let p and w represent the speeds of the plane and the wind. The relation between time, speed, and distance is ...
speed = distance/time
p +w = (2565 mi)/(4.5 h) = 570 mi/h
p -w = (2205 mi)/(4.5 h) = 490 mi/h
Adding these speeds, we get ...
(p +w) +(p -w) = (570) +(490) mi/h
2p = 1060 mi/h
p = 530 mi/h
Then the speed of the wind is ...
w = 570 mi/h -p = (570 -530) mi/h = 40 mi/h
The plane's speed is 530 mi/h; the wind speed is 40 mi/h.
Answer: called tthe term of an algebraic expression.
<h3 /><h3>
Step-by-step explanation: We know an algebraic expression is a collection or combination of constant and variables of one or more terms, which are separated by the fundamental operations (+, –, × and ÷).</h3><h3 /><h3>
Some of the examples of algebraic expression are 7b + 5m, 5x + 3y + 10, 5x/y + 3, x + y + z, etc.</h3><h3>
Terms of an algebraic expression:</h3><h3>
Each part of an algebraic expression which are separated by plus sign (+) or minus sign (-) is called the term of an algebraic expression. It’s important to remember that the division sign (÷) or multiplication sign (×) does not separate the terms of an algebraic expression.</h3>
Examples of algebraic expressions and their terms:
(i) x + 10
We observe that the number of terms used in the expression x + 10 is 2. The terms are x and 10.
(ii) 5m + 2n - 7
We observe that the number of terms used in the expression 5m + 2n – 7 is 3. The terms are 5m, 2n and 7.
(iii) 3a/b
We observe that the number of term used in the expression 3a/b is 1. The term is 3a/b.
(iv) 3xy + 7xz + 2yz - 6
We observe that the number of terms used in the expression 3xy + 7xz + 2yz - 6 is 4. The terms are 3xy, 7xz, 2yz and 6.
) 2abc + 1
We observe that the number of terms used in the expression 2abc + 1 is 2. The terms are 2abc and 1.
Therefore, the algebraic expressions are either simple or compound.
(i) Simple algebraic expressions consist of one term.
(ii) Compound algebraic expressions consist of two or more terms.
Answer:
64 textbooks
Step-by-step explanation:
the first two teachers had 21 students each that's 21+21=42
the other teacher had 22 students so apparently all the textbooks handed to the students are,21+21+22=64
There are 10 fish in the tank
<em><u>Solution:</u></em>
Given that, volume of a tank is 50 cubic feet
Density is 0.2 fish over feet cubed
<em><u>To find: Number of fish in the tank</u></em>
Number of fish in the tank is found by multiplying the volume of tank and density
<em><u>The formula is given by:</u></em>
<em><u>Substituting the given values, we get</u></em>
Thus there are 10 fish in the tank
