Answer:
The answer to your question is 2², 5 and, 7
Step-by-step explanation:
Data
140
Process
1.- Find the prime factors of 140, starting with 2, then, 3, 5, 7, etc
140 2
70 2
35 5
7 7
1
2.- Write 140 as a composition of prime factors
140 = (2²)(5)(7)
3.- Conclusion
The prime factors of 140 are 2², 5 and 7
You do them in the order of operations, for example, on the 1st one you did 3x5 first and got 15, and then you added 2 and got a total of 17. On the second one, you did2x4 which is 8 and the you added 3 and made it a total of 11. So basically you do the last 2 boxes first, the add/subtract the first from the total of the other 2.
Answer:
Step-by-step explanation:
y = (x^2 + 4x) + 2
Take 1/2 of the linear term 4/2 = 2 and square that result. 2^2 = 4.
Put it after 4x
y = (x^2 + 4x + 4) +2 Subtract what you put inside the brackets on the outside.
y = (x^2 + 4x + 4) + 2 - 4 Combine the right.
y = (x^2 + 4x + 4) - 2 Express the brackets as a square.
y = (x + 2)^2 - 2
That's your answer
a = 1
h = 2
k = -2
175
You are adding 82 to 93
Cot(theta) = 1/tan(theta) = cos(theta)/sin(theta) =
cos(theta)/sqrt(1-cos^2(theta))
cot(theta) = cos(theta)/sqrt(1-cos^2(theta))
cot^2(theta)(1-cos^2(theta))=cos^2(theta)
(cot^2(theta)+1)cos^2(theta)=cot^2theta
cot(theta)/sqrt(cot^2(theta)+1)