Since the problem states "at least" we need to also find probability of 3 H or 4 H or 5 H
Now find the probability of flipping a head 4 times;
⁴
= (1/16)
Now probability of flipping a head 3 times: (4C3)(1/2)⁴ = 4/16
Probability of flipping a head 2 times; (4C2)(1/2)⁴=6/16
(1/16)+(4/16)+(6/16)=11/16
Probability of flipping a fair coin 4 times with at least 2 heads is 11/16.
Hope I helped :)
Answer:
4 whole days
Step-by-step explanation:
If he wrote 3 pages each day and he has to write 12 pages then it would take him 4 days.
A = 500(1 + 0.002)^(10 x 12) = 500(1.002)^120 = 500(1.2704) = $635.47
B. 18m(2n-3)
18m(2n-3)
= 18m(2n) - 3(18m)
= 36mn -54m