F(x)=6x^2-x^2+x-5 and g(x)=0 find (f*g)(x) and (g*f)(x)
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The formulas for arc length and area of a sector are quite close in their appearance. The formula for arc length, however, is related to the circumference of a circle while the area of a sector is related to, well, the area! The arc length formula is 
. Notice the "2*pi*r" which is the circumference formula. The area of a sector is 
. Notice the "pi*r squared", which of course is the area of a circle. In our problem we are given the arc length and the radius. What we do not have that we need to then find the area of a sector of the circle is the measure of the central angle, beta. Filling in accordingly, 
. Simplifying by multiplying by 360 on both sides and then dividing by 36 on both sides gives us that our angle has a measure of 60°. Now we can use that to find the area of a sector of that same circle. Again, filling accordingly, 
, and 
. When you multiply in the value of pi, you get that your area is 169.65 in squared.