H(t) = Ho +Vot - gt^2/2
Vo = 19.6 m/s
Ho = 58.8 m
g = 9.8 m/s^2
H(t) = 58.8 + 19.6t -9.8t^2/2 = 58.8 + 19.6t - 4.9t^2
Maximun height is at the vertex of the parabole
To find the vertex, first find the roots.
58.8 + 19.6t - 4.9t^2 = 0
Divide by 4.9
12 + 4t - t^2 = 0
Change sign and reorder
t^2 - 4t -12 = 0
Factor
(t - 6)(t + 2) =0 ==> t = 6 and t = -2.
The vertex is in the mid point between both roots
Find H(t) for: t = [6 - 2]/2 =4/2 = 2
Find H(t) for t = 2
H(6) = 58.8 + 19.6(2) - 4.9(2)^2 = 78.4
Answer: the maximum height is 78.4 m
Answer: n = -2
Step-by-step explanation:
Answer:
The answer is below
Step-by-step explanation:
a) Let negative means the turtle position when descending and positive for going up. Therefore since the turtle was 850 meters below see level, it was at -850. It then moves 165 meters up, hence its new position is -685 meters (-850 + 165). Lastly it moves down 165 meters, hence its new position is -850 meters (-685 - 165)
b) The change in position is the sum of the movements = +165 - 165 = 0 meters.