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lord [1]
3 years ago
4

The root-mean-square speed (thermal speed) for a certain gas at 100 degree C is 0.500 km/s. If the temperature of the gas is now

increased to 200 degree C, the root-mean-square(thermal) speed will be closest to 563 m/s. 1000 m/s 634m/s 707 m/s 804 m/s

Physics
2 answers:
Anettt [7]3 years ago
7 0

Answer: 707m/s

Explanation:

The formulae for the thermal speed (Vrms) is given below as

Vrms =√3KT/m

K, T and m are all constants which implies that

Vrms is proportional to the square root of temperature.

That's (Vrms)1/√T1 = (Vrms)2/√T2

(Vrms)1 = 0.5km/s, T1 = 100°c, (Vrms)2 =?, T2 = 200°c

By substituting we have that

0.5/√100 = (Vrms)2/√200

By cross multiplication

0.5×√200 = (Vrms)2×√100

0.5 × √200 = (Vrms)2 × 10

(Vrms)2 = (0.5 × √200)/10

(Vrms)2 = 0.707 km/s.

By converting to m/s, we multiply 0.707 km/s by 1000

(Vrms)2 = 0.707×1000 = 707 m/s

Travka [436]3 years ago
7 0

Explanation:

Below is an attachment containing the solution.

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