Answer:
Explanation:
In the process of convection, first the molecules of substance gets heat and becomes heated. As the molecules heated, their density decreases and hence they rises up. And the molecules which are cooler, they fall and comes in contact of higher temperature and then they rises up. the process repeats itself until the entire liquid heated uniformly.
Answer:
the sp³ orbital, is a very directional orbital that forms the bonds called covalent. the material is an electrical Insulator. hardness of the material comes from the energy needed to break the covalent bonds (sp³)
Explanation:
Carbon has several structures, for its different ways of bonding, in all these the orbital s is excited and mixed with the orbitals p, creating hybrid orbitals sp³, sp² and sp, there are some π orbitals around the latter.
Each type of hybrid orbital is linked differently, the sp³ orbital, is a very directional orbital that forms the bonds called covalent, where when it binds to another atom they share an electron, therefore the 4 sp³ orbitals form a stable molecule with full orbitals (8 electrons).
As the electrons are in the direction of the links, they cannot be easily moved, so the material is an electrical Insulator.
The hardness of the material comes from the energy needed to break the covalent bonds (sp³), there are only a few directions in which the links can be separated
Answer:
V₀y = 0 m/s
t = 2.47 s
V₀ₓ = 61.86 m/s
Vₓ = 61.86 m/s
Explanation:
Since, the ball is hit horizontally, there is no vertical component of velocity at initial point. So, the initial vertical velocity (V₀y) will beL
<u>V₀y = 0 m/s</u>
For the initial vertical velocity of golf ball we consider the vertical motion and apply 2nd equation of motion:
Y = V₀y*t + (0.5)gt²
where,
Y = Height = 30 m
g = 9.8 m/s²
t = time to hit the ground = ?
Therefore,
30 m = (0 m/s)(t) + (0.5)(9.8 m/s²)t²
t² = 30 m/4.9 m/s²
t = √6.122 s²
<u>t = 2.47 s</u>
For initial vertical velocity we analyze the horizontal motion of the ball. We neglect the frictional effects in horizontal motion thus the speed remains uniform. Hence,
V₀ₓ = Xt
where,
V₀ₓ = Initial vertical Velocity = ?
X = Horizontal Distance = 25 m
Therefore,
V₀ₓ = (25 m)(2.47 s)
<u>V₀ₓ = 61.86 m/s</u>
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Due, to uniform motion in horizontal direction:
Final Vertical Velocity = Vₓ = V₀ₓ
Vₓ = 61.86 m/s
Answer:
See the explanation below
Explanation:
The watt (the power) is equal to the relationship between the work and the time in which that work is performed.
where:
W = work [J] (units of Joules)
t = time [s].
Now 1000 [W] are equal to 1 [kW]
And 1000000 [W] are equal to 1 [MW]
The horsepower is the unit of power in the imperial system of units.
And 745.7 [W] are equal to 1 [Hp]
Answer:
a) v = 54.7m/s
b) v = (58 - 1.66a) m/s
c) t = 69.9 s
d) v = -58.0 m/s
Explanation:
Given;
The height equation of the arrow;
H = 58t - 0.83t^2
(a) Find the velocity of the arrow after two seconds. m/s;
The velocity of the arrow v can be given as dH/dt, the change in height per unit time.
v = dH/dt = 58 - 2(0.83t) ......1
At t = 2 seconds
v = dH/dt = 58 - 2(0.83×2)
v = 54.7m/s
(b) Find the velocity of the arrow when t = a. m/s
Substituting t = a into equation 1
v = 58 - 2(0.83×a)
v = (58 - 1.66a) m/s
(c) When will the arrow hit the surface? (Round your answer to one decimal place.) t = s
the time when H = 0
Substituting H = 0, we have;
H = 58t - 0.83t^2 = 0
0.83t^2 = 58t
0.83t = 58
t = 58/0.83
t = 69.9 s
(d) With what velocity will the arrow hit the surface? m/s
from equation 1;
v = dH/dt = 58 - 2(0.83t)
Substituting t = 69.9s
v = 58 - 2(0.83×69.9)
v = -58.0 m/s