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guajiro [1.7K]
2 years ago
6

PLS ANSWER REAL ANSWERS ONLY

Physics
1 answer:
Julli [10]2 years ago
7 0

Answer:

Who is moving the fastest: Green triangle

What is the slope of Blue Diamonds: 5/6 or 5/7, can’t tell completely

<h2><u>Hope This helped!</u></h2>

You might be interested in
How long was a 60 W light bulb turned on if it used a total of 580 J of energy?
icang [17]
Here's the tool you need.  You can't answer the question without this:

           "1 watt"
means
           "1 joule of energy, generated, used, or moved, every second".

So      60 watts  =  60 joules per second

           Total energy generated,
            used, or moved                  = (power) x (time).

                                     580 joules  =  (60 watts) x (time)

Divide each side
by  (60 watts):              Time  =  (580 joules) / (60 joules/sec) 

                                               =  (9 and 2/3)  seconds  .
7 0
3 years ago
A new conveyor system at the local packaging plant will utilize a motor powered mechanical arm to exertion average force of 890N
valkas [14]

Answer:

power =( 890 N x 12 m ) / 22 s=

=   485 Watts

Explanation:

4 0
2 years ago
Motor oil , with a viscosity of 0 . 250 Ns / m2 , is flowing through a tube that has a radius of 5 . 00 mm and is 25 . 0 cm long
Thepotemich [5.8K]

Answer:

1.1775 x 10^-3 m^3 /s

Explanation:

viscosity, η = 0.250 Ns/m^2

radius, r = 5 mm = 5 x 10^-3 m

length, l = 25 cm = 0.25 m

Pressure, P = 300 kPa = 300000 Pa

According to the Poisuellie's formula

Volume flow per unit time is

V=\frac{\pi \times Pr^{4}}{8\eta l}

V=\frac{3.14 \times 300000\times \left ( 5\times 10^{-3} \right )^{4}}{8\times 0.250\times 0.25}

V = 1.1775 x 10^-3 m^3 /s

Thus, the volume of oil flowing per second is 1.1775 x 10^-3 m^3 /s.

3 0
3 years ago
At t = 0 a car has a speed of 30 m/s. At t = 6 s, its speed is 14 m/s.
Hitman42 [59]

Answer:

-2.67 m/s²

Explanation:

a = Δv / Δt

a = (14 m/s − 30 m/s) / (6 s − 0 s)

a = -2.67 m/s²

4 0
3 years ago
A piece of bismuth with a mass of 4.06 g 4.06 g gains 423 J 423 J of heat. If the specific heat of bismuth is 0.123 J / ( g ° C
Sholpan [36]

Answer: 846°C

Explanation:

The quantity of Heat Energy (Q) required to heat bismuth depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Given that:

Q = 423 joules

Mass of bismuth = 4.06g

C = 0.123 J/(g°C)

Φ = ?

Then, Q = MCΦ

423 J = 4.06g x 0.123 J/(g°C) x Φ

423 J = 0.5J/°C x Φ

Φ = (423J/ 0.5g°C)

Φ = 846°C

Thus, the change in temperature of the sample is 846°C

4 0
3 years ago
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