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Rama09 [41]
3 years ago
8

Kyle is raising funds for his company by selling preferred stock. The preferred stock has a par value of ​$122 and a dividend ra

te of 6.5​%. The stock is selling for ​$84.39 in the market. Kyle hires Wilson Investment Bankers to sell the preferred stock. Wilson charges a fee of 1​% on the sale of preferred stock. What is the cost of preferred stock for Kyle using the investment​ banker?
Mathematics
1 answer:
kirza4 [7]3 years ago
6 0

no i think your answer is 9082

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Betty likes to skate at a skate park that is due south of her school and due west of her
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Which of the following transformations has the same result as a rotation of 90 degrees clockwise?
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The best and most correct answer among the choices provided by your question is the second choice or letter B.

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Log(x-2)+log2=2logy<br>log(x-3y+3)=0​
In-s [12.5K]

Answer:

<h2>x = 4 and y = 2 or x = 10 and y = 4</h2>

Step-by-step explanation:

\left\{\begin{array}{ccc}\log(x-2)+\log2=2\log y&(1)\\\log(x-3y+3)=0&(2)\end{array}\right

===========================\\\text{DOMAIN:}\\\\x-2>0\to x>2\\y>0\\x-3y+3>0\to x-3y>-3\\=====================\\\\\text{We know:}\ \log_ab=c\iff a^c=b,\\\\\text{therefore}\ \log_ab=0\iff a^0=b\to b=1\\\\\text{From this we have}\\\\\log(x-3y+3)=0\iff x-3y+3=1\qquad\text{add}\ 3y\ \text{to both sides}\\\\x+3=3y+1\qquad\text{subtract 3 from both isdes}\\\\\boxed{x=3y-2}\qquad(*)\\\\\text{Substitute it to (1)}

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y^2=(3y)(2)+(-4)(2)\\\\y^2=6y-8\qquad\text{subtract}\ 6y\ \text{from both sides}\\\\y^2-6y=-8\qquad\text{add 8 to both sides}\\\\y^2-6y+8=0\\\\y^2-2y-4y+8=0\\\\y(y-2)-4(y-2)=0\\\\(y-2)(y-4)=0\iff y-2=0\ \vee\ y-4=0\\\\\boxed{y=2\ \vee\ y=4}\in D

\text{Put the values of}\ y\ \text{to }\ (*):\\\\\text{for}\ y=2:\\\\x=3(2)-2\\\\x=6-2\\\\\boxed{x=4}\in D\\\\\text{for}\ y=4:\\\\x=3(4)-2\\\\x=12-2\\\\\boxed{x=10}\in D

4 0
3 years ago
HELP ME!!!!!!
sdas [7]

Answer:

A. Minimum = 54, Q1= 69.5, Median = 75, Q3= 106, Maximum = 183

Step-by-step explanation:

Arranging the data set in order from least to greastest we get:

54, 68, 71, 72, 75, 84, 104, 108, 183

From this, we can see that the minimum value is 54 and the maximum value is 183.

Taking a number off one by one on each side of the data set gives the median. In the middle lies 75, so that is our median

To find quartile ranges, split the data set into two where the median lies, then, find the median of those two data sets. The medians will be the values of the upper (Q3) and lower quartiles (Q1).

Q1: 54, 68, 71, 72

68 + 71 = 139
139 ÷ 2 = 69.5

-----

Q3: 84, 104, 108, 183

104 + 108 = 212

212 ÷ 2 = 106

Option A is the only answer with all of these values, therefore, it is the answer.

hope this helps!

3 0
2 years ago
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