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nevsk [136]
3 years ago
7

What is the value of the expression 4x−y/2y x when x = 3 and y = 3? −3 1 9 18

Mathematics
1 answer:
ziro4ka [17]3 years ago
5 0
(4x - y)/(2y + x) when x = 3 and y = 3 is
(4(3) - 3)/(2(3) + 3) = (12 - 3)/(6 + 3) = 9/9 = 1

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Find the length of AB
Lady_Fox [76]

Hey there! :)

Answer:

arc AB = 2.5π in (in terms of pi) or ≈7.85 in. (pi = 3.14)

Step-by-step explanation:

Begin by finding the circumference of the circle. Use the formula:

C = 2rπ

C = 2(9)π

C = 18π.

Since ∠AQB equals 50°, set up a ratio to find the length of arc AB:

\frac{50}{360}  = \frac{x}{18\pi }

Cross multiply:

50 · 18π = 360x

900π = 360x

Divide both sides by 360:

x = 2.5π in, or ≈7.85 in.

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Write 4/27 as the product of a prime raised to a power​
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Answer:

write 4/27 as the product of a prime raised to a power

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3 years ago
Which question is a statistical question?
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3 years ago
For the function y=3x2: (a) Find the average rate of change of y with respect to x over the interval [3,6]. (b) Find the instant
nirvana33 [79]

Answer:

The instantaneous rate of change of y with respect to x at the value x = 3 is 18.

Step-by-step explanation:

a) Geometrically speaking, the average rate of change of y with respect to x over the interval by definition of secant line:

r = \frac{y(b) -y(a)}{b-a} (1)

Where:

a, b - Lower and upper bounds of the interval.

y(a), y(b) - Function exaluated at lower and upper bounds of the interval.

If we know that y = 3\cdot x^{2}, a = 3 and b = 6, then the average rate of change of y with respect to x over the interval is:

r = \frac{3\cdot (6)^{2}-3\cdot (3)^{2}}{6-3}

r = 27

The average rate of change of y with respect to x over the interval [3,6] is 27.

b) The instantaneous rate of change can be determined by the following definition:

y' =  \lim_{h \to 0}\frac{y(x+h)-y(x)}{h} (2)

Where:

h - Change rate.

y(x), y(x+h) - Function evaluated at x and x+h.

If we know that x = 3 and y = 3\cdot x^{2}, then the instantaneous rate of change of y with respect to x is:

y' =  \lim_{h \to 0} \frac{3\cdot (x+h)^{2}-3\cdot x^{2}}{h}

y' =  3\cdot \lim_{h \to 0} \frac{(x+h)^{2}-x^{2}}{h}

y' = 3\cdot  \lim_{h \to 0} \frac{2\cdot h\cdot x +h^{2}}{h}

y' = 6\cdot  \lim_{h \to 0} x +3\cdot  \lim_{h \to 0} h

y' = 6\cdot x

y' = 6\cdot (3)

y' = 18

The instantaneous rate of change of y with respect to x at the value x = 3 is 18.

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