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nata0808 [166]
3 years ago
7

100 POINTS!!!!

Mathematics
2 answers:
Law Incorporation [45]3 years ago
5 0

Answer:

Part A: In order to find the x-intercepts, you should set f(x)=0. Then, .  and .

Part B: From the function, it is visible that it is going to be a minimum, because the function is cup-size. Vertex coordinates can be calculated by the formula . Then  and . The vertex coordinates are (-1.25, -0.125)

Part C: By using the vertex coordinates, we can construct the vertex of the function and then using the information about the x-intercept we can complete the function. The function looks like in the picture below.

Step-by-step explanation:

arlik [135]3 years ago
4 0

Answer:

Part A: In order to find the x-intercepts, you should set f(x)=0. Then, .  and .

Part B: From the function, it is visible that it is going to be a minimum, because the function is cup-size. Vertex coordinates can be calculated by the formula . Then  and . The vertex coordinates are (-1.25, -0.125)

Part C: By using the vertex coordinates, we can construct the vertex of the function and then using the information about the x-intercept we can complete the function. The function looks like in the picture below.

Step-by-step explanation:

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3 years ago
Ryder Industries is considering a project that will produce cash inflows of $92,000 a year for five years. What is the internal
RSB [31]

Answer:

20.02%

Step-by-step explanation:

Formula : NVP = 0 =-P_0 + \frac{P_1}{(1+IRR)} + \frac{P_2}{(1+IRR)^2} + . . . +\frac{P_n}{(1+IRR)^n}

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n = 1,2,3,4,5

Substitute the values in the formula :

0 =-275000 + \frac{92000}{(1+IRR)} + \frac{92000}{(1+IRR)^2} + \frac{92000}{(1+IRR)^3}+\frac{92000}{(1+IRR)^4}+\frac{92000}{(1+IRR)^5}

275000 = \frac{92000}{(1+IRR)} + \frac{92000}{(1+IRR)^2} + \frac{92000}{(1+IRR)^3}+\frac{92000}{(1+IRR)^4}+\frac{92000}{(1+IRR)^5}

Solving for IRR using calculator

IRR = 20.02

Hence the internal rate of return if the initial cost of the project is $275,000 is 20.02%

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3 years ago
Using an ordered alphabet of 26 letters, how many ways are there to choose a set of six letters such that no two letters in the
mestny [16]
To find our solution, we can start off by creating a string of 27 boxes, all followed by the letters of the alphabet. Underneath the boxes, we can place 6 pairs of boxes and 15 empty boxes.The stars represent the six letters we pick. The empty boxes to the left of the stars provide the "padding" needed to ensure that no two adjacent letters are chosen. We can create this - 
\binom {21} {6}= \frac{21*20*19*18*17*16}{6*5*4*3*2*1} =21*19*17*8=54264
Thus, the answer is that there are \boxed{54264} ways to choose a set of six letters such that no two letters in the set are adjacent in the alphabet. Hope this helped and have a phenomenal New Year! <em>2018</em>
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3 years ago
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