let each box length be 1
<em><u>for</u></em><em><u> </u></em><em><u>white</u></em><em><u> </u></em><em><u>triangle</u></em>
area = ½bh
=½(4)(2)
=4
<em><u>f</u></em><em><u>o</u></em><em><u>r</u></em><em><u> </u></em><em><u>o</u></em><em><u>r</u></em><em><u>a</u></em><em><u>n</u></em><em><u>g</u></em><em><u>e</u></em><em><u> </u></em><em><u>t</u></em><em><u>r</u></em><em><u>i</u></em><em><u>a</u></em><em><u>n</u></em><em><u>g</u></em><em><u>l</u></em><em><u>e</u></em>
area=½(2)(3)
=3
<em><u>f</u></em><em><u>o</u></em><em><u>r</u></em><em><u> </u></em><em><u>b</u></em><em><u>l</u></em><em><u>u</u></em><em><u>e</u></em><em><u> </u></em><em><u>m</u></em><em><u>a</u></em><em><u>r</u></em><em><u>k</u></em><em><u>e</u></em><em><u>d</u></em><em><u> </u></em><em><u>b</u></em><em><u>o</u></em><em><u>x</u></em><em><u>e</u></em><em><u>s</u></em>
each of the box
area=l²
=(1)²
=1
there are 16 boxes
so the total area will be 16
total area of the hexagon = 4+3+16
=23 square units
Answer:

Step-by-step explanation:
Area of the shaded region = area of the large rectangular - area of the small rectangle
Area of rectangle is given as l*w
Area of the large rectangle = 
Expand


Area of large rectangle 
Area of small rectangle = 


Area of small rectangle = 
Area of shaded region = 

Collect like terms


While I cannot see your answer choices, the correct answer would be one that has a coefficient that is a multiple of 3 and has an x raised to an exponent of no more than 2. It could have any other variables in it.
The reason this has to be is because of the GCF. Since 3 is part of the GCF, and the other monomial has a coefficient of 3, this means the missing monomial must be divisible by 3 as well.
Since x² is part of the GCF, the missing monomial must contain x². However, if it were to contain x³ or anything larger, the GCF would have x with a higher exponent.