Question

What is the force of gravity (in Newtons) acting between the Earth and a 100-kg person who is on board the International Space Station, 350 km above the surface of the Earth?

Answer 1

Answer:

$f_{G}=317877.55 N = 317.8 kN$

Step-by-step explanation:

$f_{G}= (G*m_{1}*m_{2})/r^{2} \\Where:\\f_{G}= force of gravity\\G=gravitational constant= 6.6x10^{-11}m^{3}kg^{-1}s^{-2}\\ m_{1}= earth mass = 5.9x10^{24}kg\\m_{2}=person mass = 100kg\\r= distance between the bodies=350km= 350 000 m$