Answer:
A = 1,13x10¹⁰
Ea = 16,7 kJ/mol
Explanation:
Using Arrhenius law:
ln k = -Ea/R × 1/T + ln(A)
You can graph ln rate constant in x vs 1/T in y to obtain slope: -Ea/R and intercept is ln(A).
Using the values you will obtain:
y = -2006,9 x +23,147
As R = 8,314472x10⁻³ kJ/molK:
-Ea/8,314472x10⁻³ kJ/molK = -2006,9 K⁻¹
<em>Ea = 16,7 kJ/mol</em>
Pre-exponential factor is:
ln A = 23,147
A = e^23,147
<em>A = 1,13x10¹⁰</em>
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I hope it helps!
Answer:
Explanation:
Hello,
Considering the given reaction's stoichiometry, grams of oxygen result:
Moreover, the mass of produced carbon dioxide turns out:
Best regards.
Answer:
15900
Explanation:
I think hope this helps!! :D
Answer: B I think, I'll put my reasoning below.
Explanation:
It's not A because removing N2 would only shift the equation the opposite way.
It's not C and D because I don't think those affect the specific amount of each reactant/product produced. I think temperature only affects the speed at which the reaction is performed, which won't affect anything in this case.
