This problem is easily solvable because radioactivity equations are common and well-established. The pseudo-first reaction is written below:
A = A₀(1/2)^(t/h)
where
A is the final amount
A₀ is the original amount
t is the time
h is the half life
5,000 = A₀(1/2)^(24,000/6,000)
Solving for A₀,
<em>A₀ = 80,000 atoms</em>
Answer:
2KOH + H₂SO₄ → K₂SO₄ + 2H₂O.
Explanation:
- This is an acid-base reaction which produces salt and water according to the balanced equation:
<em>2KOH + H₂SO₄ → K₂SO₄ + 2H₂O.</em>
<em></em>
it is clear that 2.0 moles of KOH react with 1.0 mole of H₂SO₄ to produce 1.0 mole of K₂SO₄ and 2.0 moles of H₂O
Answer:
the 4th one
Explanation:
kinitc energy formula is1/2mv^
there is mass ,and velocity (speed)
I hope it help