Answer:
+1
Explanation:
Na₂O₂
NOTE: the oxidation number of oxygen is always –2 except in peroxides where it is –1.
Thus, we can obtain the oxidation number of sodium (Na) in Na₂O₂ as illustrated below:
Na₂O₂ = 0 (oxidation number of ground state compound is zero)
2Na + 2O = 0
O = –1
2Na + 2(–1) = 0
2Na – 2 = 0
Collect like terms
2Na = 0 + 2
2Na = 2
Divide both side by 2
Na = 2/2
Na = +1
Thus, the oxidation number of sodium (Na) in Na₂O₂ is +1
Answer:
I am so confused about this i am so sorry but i cant there is to much going on
Explanation:
You should keep the cough drop whole. This maintains the largest surface-to-volume ratio and slows the dissolution of the cough drop.
<h3>Delay of drug action</h3>
The action of the drug can be delayed to either reduce adverse effect if the drugs to the body or to enhance its therapeutic purposes.
Because the throat is dry, the therapeutic purposes of the cough drop would only be achieved if it's dissolution is delayed in the mouth.
To do so, the cough drop should be kept whole to maintain the largest surface-to-volume ratio. This would slow the dissolution of the cough drop.
Learn more about drug here:
brainly.com/question/26254731
Solution :
a). Applying the energy balance,
![$0=[mc(T_f-T_i)_{iron}] + [mc(T_f-T_i)_{water}]$](https://tex.z-dn.net/?f=%240%3D%5Bmc%28T_f-T_i%29_%7Biron%7D%5D%20%2B%20%5Bmc%28T_f-T_i%29_%7Bwater%7D%5D%24)
b). The entropy change of iron.
= -9.09 kJ-K
Entropy change of water :
= 10.76 kJ-K
So, the total entropy change during the process is :
= -9.09 + 10.76
= 1.67 kJ-K
c). Exergy of the combined system at initial state,
Therefore, energy of the combined system at the initial state is
= 63.94 -13.22
= 50.72 kJ
Similarly, Exergy of the combined system at initial state,
Thus, energy or the combined system at the final state is :
= 216.39 - 9677.95
= -9461.56 kJ
d). The wasted work
= 50.72 + 9461.56
= 9512.22 kJ
