As brown is dominant, all four children will have brown eyes.
Hi the T and B cells change after contact with the pathogen is a-- acquired-- immune response.
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Answer: Lek Polygyny
Explanation:
Polygyny is a mating system inwhich one male is associated with multiple females. This mating system is found in a few birds and insects, but is most common in mammals. Polygyny is a strategy used by males to increase their reproductive fitness.
Lek polygyny is a system where male aggregate at a location and try to attract females for mating and the females leave after mating. It is believed that males attract more mate in this way than in isolation.
Answer:
pH = 3.215
Explanation:
From the given information;
Using the equation for the dilution of a stock solution:
Since moles of C5H5N = moles of HNO3
Then:
![M_{C_5H_5N}\times V_{C_5H_5N}= M_{HNO_3}\times V_{HNO_3}](https://tex.z-dn.net/?f=M_%7BC_5H_5N%7D%5Ctimes%20V_%7BC_5H_5N%7D%3D%20M_%7BHNO_3%7D%5Ctimes%20V_%7BHNO_3%7D)
![0.0750 M \times 2.65 L = 0.407 M \times V_{HNO_3}](https://tex.z-dn.net/?f=0.0750%20M%20%5Ctimes%202.65%20L%20%3D%200.407%20M%20%5Ctimes%20V_%7BHNO_3%7D)
![V_{HNO_3}= \dfrac{0.0750 M \times 2.65 L}{0.407 M}](https://tex.z-dn.net/?f=V_%7BHNO_3%7D%3D%20%5Cdfrac%7B0.0750%20M%20%5Ctimes%202.65%20L%7D%7B0.407%20M%7D)
![V_{HNO_3}=488.33 \ mL](https://tex.z-dn.net/?f=V_%7BHNO_3%7D%3D488.33%20%5C%20mL)
The reaction between C5H5NH and H2O is as follows:
⇄ ![C_5H_5N + H_3O^+](https://tex.z-dn.net/?f=C_5H_5N%20%2B%20H_3O%5E%2B)
![Molarity \ of \ C_5H_5N^+H = \dfrac{moles}{addition \ of\ the\ total\ volume}](https://tex.z-dn.net/?f=Molarity%20%20%5C%20of%20%5C%20C_5H_5N%5E%2BH%20%3D%20%5Cdfrac%7Bmoles%7D%7Baddition%20%5C%20of%5C%20%20the%5C%20%20total%5C%20volume%7D)
![Molarity \ of \ C_5H_5N^+H = \dfrac{0.0750 \ M \times 2.65 \ L}{2.65 \ L + 0.48833 \ L}](https://tex.z-dn.net/?f=Molarity%20%20%5C%20of%20%5C%20C_5H_5N%5E%2BH%20%3D%20%5Cdfrac%7B0.0750%20%5C%20M%20%5Ctimes%202.65%20%5C%20L%7D%7B2.65%20%5C%20L%20%2B%200.48833%20%5C%20L%7D)
![Molarity \ of \ C_5H_5N^+H = \dfrac{0.19875 \ ML}{3.13833 L }](https://tex.z-dn.net/?f=Molarity%20%20%5C%20of%20%5C%20C_5H_5N%5E%2BH%20%3D%20%5Cdfrac%7B0.19875%20%5C%20ML%7D%7B3.13833%20L%20%7D)
![= \ 0.06333\ M](https://tex.z-dn.net/?f=%3D%20%5C%200.06333%5C%20M)
Now, the next step is to draw out the I.C.E table.
⇄ ![C_5H_5N + H_3O^+](https://tex.z-dn.net/?f=C_5H_5N%20%2B%20H_3O%5E%2B)
I 0.06333 0 0
C - x x x
E 0.06333 -x x x
![K_a = \dfrac{10^{-14}}{1.7 \times 10^{-19}} \\ \\ K_a = 5.8824 \times 10^{-6}](https://tex.z-dn.net/?f=K_a%20%20%3D%20%5Cdfrac%7B10%5E%7B-14%7D%7D%7B1.7%20%5Ctimes%2010%5E%7B-19%7D%7D%20%5C%5C%20%5C%5C%20%20K_a%20%3D%205.8824%20%5Ctimes%2010%5E%7B-6%7D)
![K_a = \dfrac{[C_5H_5N][H_3O^+] }{[C_5H_5N^+H] } \\ \\ 5.8824 \times 10^{-6} = \dfrac{x^2}{0.06333 - x}](https://tex.z-dn.net/?f=K_a%20%3D%20%5Cdfrac%7B%5BC_5H_5N%5D%5BH_3O%5E%2B%5D%20%7D%7B%5BC_5H_5N%5E%2BH%5D%20%7D%20%20%5C%5C%20%5C%5C%20%205.8824%20%5Ctimes%2010%5E%7B-6%7D%20%3D%20%5Cdfrac%7Bx%5E2%7D%7B0.06333%20-%20x%7D)
Assuming x < 0.06333
![x^2 = 5.8824 \times 10^{-6} \times 0.06333](https://tex.z-dn.net/?f=x%5E2%20%3D%205.8824%20%5Ctimes%2010%5E%7B-6%7D%20%5Ctimes%200.06333)
Then
![x^2 = 3.72532392 \times 10^{-7} \\ \\ x= \sqrt{3.72532392 \times 10^{-7}} \\ \\ x = 6.1035 \times 10^{-4} \ M](https://tex.z-dn.net/?f=x%5E2%20%3D%203.72532392%20%5Ctimes%2010%5E%7B-7%7D%20%5C%5C%20%5C%5C%20x%3D%20%5Csqrt%7B3.72532392%20%5Ctimes%2010%5E%7B-7%7D%7D%20%5C%5C%20%5C%5C%20%20x%20%3D%206.1035%20%5Ctimes%2010%5E%7B-4%7D%20%5C%20M)
![[H_3O^+] = x = 6.1035 \times 10^{-4} \ M \\ \\ pH = -log (6.1035 \times 10^{-4}) \\ \\ \mathbf{\\ pH = 3.215}](https://tex.z-dn.net/?f=%5BH_3O%5E%2B%5D%20%3D%20%20x%20%3D%206.1035%20%5Ctimes%2010%5E%7B-4%7D%20%5C%20M%20%20%5C%5C%20%5C%5C%20%20pH%20%3D%20-log%20%286.1035%20%5Ctimes%2010%5E%7B-4%7D%29%20%5C%5C%20%5C%5C%20%5Cmathbf%7B%5C%5C%20pH%20%3D%203.215%7D)