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nikitadnepr [17]
3 years ago
15

a company a company paid $48 for two cases of printer paper each case contains 12 packages of paper next month the company offic

e manager needs a order of 180 packages of the same paper of the same paper if the price per package does not change what would be the total cost of next month order
Mathematics
1 answer:
zalisa [80]3 years ago
6 0

Answer:

$360

Step-by-step explanation:

So for 2 cases that have 12 packs its $48 which means each case cost $24, so keep that for later now look closely, they need 180 PACKAGES not cases so if there are 12 packages in one case divide 180/12 and you will get 15, so that means you need 15 cases, so take the $24 per case and multiply that by the 15 cases you need and boom...it will cost the company $360 for next months order :)

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Five surf shops sell the same pair of flip-flops for the following prices: $17.00, $15.50, $15.00, $18.00, $15.00. Find the mean
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Answer:

Mean: $16.1

Median: $15.00

Mode:$15.00

The mode best describes the data, so the mean is the better measure of variability.

Step-by-step explanation:

How to find the mean:

Add up each value on the data set, then divide it by the number of values on the data set. (Example: $17.00 + $15.50+$15.00+$18.00+$15.00= 80.5/5=16.1)

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4 0
2 years ago
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By selling a watch to Rahim, Ravi gainee Rs 50. Apurva bought the same watch from Rahim who sold at a loss of Rs 20. If Apurva p
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2 years ago
A school chorus has 90 sixth-grade students and 75 seventh-grade students. The music director wants to make groups of performers
Vera_Pavlovna [14]

Answer:

a) 15 is the largest number of groups that can be made.

b) There would 6 sixth grade students and 5 seventh grade students in each group.

Step-by-step explanation:

Number of sixth-grade students = 90

Number of seventh-grade students = 75

a) What is the largest number of groups that could be formed?

Since the music director wants to make groups with the same combination of sixth and seventh grade students in each group,

The greatest common factor (GCF) of the number of sixth and seventh grade students would give us the required combination.

Factor of 90 = 2*45 = 2*3*15 = 2*3*3*5

Factor of 75 = 3*25 = 3*5*5

The greatest common factors are 3 and 5

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Therefore, 15 is the largest number of groups that can be made.

b. If that many groups are formed, how many students of each grade level would be in each group?

Sixth grade = 90/15 = 6

Seventh grade = 75/15 = 5

Therefore, there would 6 sixth grade students and 5 seventh grade students in each group.

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