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trapecia [35]
3 years ago
8

Consider the classes below: public class TestA { public static void main(String[] args) { int x = 2; int y = 20 int counter = 0;

for (int j = y % x; j < 100; j += (y / x)) { counter++; } } } public class TestB { public static void main(String[] args) { int counter = 0; for (int j = 10; j > 0; --j) { ++counter; } } }
Computers and Technology
1 answer:
Natali5045456 [20]3 years ago
8 0

Answer:

Option d (neither a or b is true) is the correct answer for the above question.

Explanation:

Missing information : The options and the main question (which is true from the following) is not mentioned in the above question.

There is a two program given in the above question and asked to justify the true statement. The options descriptions are as follows:-

  • Option a states that the value of a counter variable will not be the same for both the program, which is not correct because both program loop will be executed 10 times only and the value of the counter will also be 10.
  • Option b states that the value of j will not be different for both the program which is also not correct because the first program loop will process from 10 to 1 by the difference of 1 but the second for loop will execute for i value from 0 to 90 by the difference of 10.
  • Option c states to right for both the option which is not correct.
  • Option d states to wrong for both the correct option. Hence option d is the correct answer.
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If 10 ft lb of torque is applied at gear A, then what is the output torque at gear D?
Mrrafil [7]
This is actually simple math.
Use the formula of Gear A/Torque > 12.8ft/lb/10 > 1.28.
Therefor the output torque is 1.28 for gear D.
6 0
3 years ago
The function below takes one parameter: a string (date_string) containing a date in the mm/dd/year format. Complete the function
Natalija [7]

Answer:

The solution code is written in Python 3.

  1. def convertDate(date_string):
  2.    date_list = date_string.split("/")
  3.    for i in range(0, len(date_list)):
  4.        date_list[i] = int(date_list[i])
  5.    return date_list  
  6. print(convertDate('06/11/1930'))

Explanation:

Firstly, create a function convertDate() with one parameter, <em>date_string</em>. (Line 1).

Next, use the Python string <em>split()</em> method to split the date string into a list of date components (month, day & year) and assign it to variable <em>date_list</em>. (Line 3) In this case, we use "/" as the separator.

However, all the separated date components in the <em>date_list</em> are still a string. We can use for-loop to traverse through each of the element within the list and convert each of them to integer using Python<em> int() </em>function. (Line 5 - 6)

At last return the final date_list as the output (Line 8)

We can test our function as in Line 11. We shall see the output is as follow:

[6, 11, 1930]

8 0
3 years ago
12.2 Sort an array in ascending order Write a program that gets a list of integers from input, and outputs the integers in ascen
notsponge [240]

Answer:

Explanation:

The following code is written in Java, it asks the user for the number of inputs that will be made and then the inputs. These inputs are placed into an array. Then the array is sorted and printed out to the terminal.

public static void sortArrayList() {

           ArrayList<Integer> sortedList = new ArrayList();

           Scanner input = new Scanner(System.in);

           System.out.println("Enter number of digits in Array");

           int numberOfInputs = input.nextInt();

           for (int i = 0; i < numberOfInputs; i++) {

                   System.out.println("Enter a number");

                   sortedList.add(input.nextInt());

           }

           int n = sortedList.size();

           for (int i = 0; i < n; i++)

               for (int j = 0; j < n-i-1; j++)

                   if (sortedList.get(j) > sortedList.get(j + 1))

                   {

                       // swap arr[j+1] and arr[j]

                       int temp = sortedList.get(j);

                       sortedList.set(j, sortedList.get(j + 1));

                       sortedList.set(j + 1, temp);

                   }

           for (int x : sortedList) {

               System.out.println(x);

           }

       }

7 0
3 years ago
for java ?(Business: check ISBN-13)ISBN-13 is a new standard for identifying books. It uses 13 digits d1d2d3d4d5d6d7d8d9d10d11d1
ludmilkaskok [199]

Answer:

In Java:

import java.util.*;

public class Main{

public static void main(String[] args) {

 Scanner input = new Scanner(System.in);

 String isbn;

 System.out.print("First 1:2 digits: ");

 isbn = input.nextLine();

 if(isbn.length()==12){

 int chksum = 0;

 for(int i = 0; i<12;i++){

     if((i+1)%2==0){      chksum+= 3 * Character.getNumericValue(isbn.charAt(i));          }

     else{          chksum+=Character.getNumericValue(isbn.charAt(i));          }  }

 chksum%=10;

 chksum=10-chksum;

 if(chksum==10){

 System.out.print("The ISBN-13 number is "+isbn+"0");}

 else{

 System.out.print("The ISBN-13 number is "+isbn+""+chksum);          }   }

 else{

     System.out.print("Invalid Input");

 }     }}

Explanation:

See attachment for explanation where comments are used to explain each line

Download txt
6 0
3 years ago
Which kind of image is indispensable and needs added text to go with ?
Harrizon [31]

Explanation:

A map is the correct answer hope that helps you.

4 0
3 years ago
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