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3 years ago

What is the value of x in the following equation? 4(x-1) = 2(x +1)

1 answer:

3 0

Start by multiplying to get rid of parentheses. Then use addition/subtraction to isolate x on one side of the equation. Finally, use division to determine the value of x.

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Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S. In other words, find the flux of

tresset_1 [31]

Because I've gone ahead with trying to parameterize $S$ directly and learned the hard way that the resulting integral is large and annoying to work with, I'll propose a less direct approach.

Rather than compute the surface integral over $S$ straight away, let's close off the hemisphere with the disk $D$ of radius 9 centered at the origin and coincident with the plane $y=0$ . Then by the divergence theorem, since the region $S\cup D$ is closed, we have

$\displaystyle\iint_{S\cup D}\vec F\cdot\mathrm d\vec S=\iiint_R(\nabla\cdot\vec F)\,\mathrm dV$

where $R$ is the interior of $S\cup D$ . $\vec F$ has divergence

$\nabla\cdot\vec F(x,y,z)=\dfrac{\partial(xz)}{\partial x}+\dfrac{\partial(x)}{\partial y}+\dfrac{\partial(y)}{\partial z}=z$

so the flux over the closed region is

$\displaystyle\iiint_Rz\,\mathrm dV=\int_0^\pi\int_0^\pi\int_0^9\rho^3\cos\varphi\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi=0$

The total flux over the closed surface is equal to the flux over its component surfaces, so we have

$\displaystyle\iint_{S\cup D}\vec F\cdot\mathrm d\vec S=\iint_S\vec F\cdot\mathrm d\vec S+\iint_D\vec F\cdot\mathrm d\vec S=0$

$\implies\boxed{\displaystyle\iint_S\vec F\cdot\mathrm d\vec S=-\iint_D\vec F\cdot\mathrm d\vec S}$

Parameterize $D$ by

$\vec s(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec k$

with $0\le u\le9$ and $0\le v\le2\pi$ . Take the normal vector to $D$ to be

$\vec s_u\times\vec s_v=-u\,\vec\jmath$

Then the flux of $\vec F$ across $S$ is

$\displaystyle\iint_D\vec F\cdot\mathrm d\vec S=\int_0^{2\pi}\int_0^9\vec F(x(u,v),y(u,v),z(u,v))\cdot(\vec s_u\times\vec s_v)\,\mathrm du\,\mathrm dv$

$=\displaystyle\int_0^{2\pi}\int_0^9(u^2\cos v\sin v\,\vec\imath+u\cos v\,\vec\jmath)\cdot(-u\,\vec\jmath)\,\mathrm du\,\mathrm dv$

$=\displaystyle-\int_0^{2\pi}\int_0^9u^2\cos v\,\mathrm du\,\mathrm dv=0$

$\implies\displaystyle\iint_S\vec F\cdot\mathrm d\vec S=\boxed{0}$

8 0

3 years ago

Please Help FAST! SOLVE EACH! Can I get step by steps also so I can understand thx I’ll mark brainlist also!!!

professor190 [17]

X-6y=6 slope: 1/6 y-intercept (0,1)

X= 0,6 y= -1, 0
X+3y+12=0 slope: 1/3
Y-intercept (0,4) x= -12, 0 Y= 0,4
8a-9b= 9/8 slope (0 ,7/8) x= -1,1 Y= -1/4,2
3a+b=7 1/3 (0,7/3) x= 4,7 Y=1,0

7 0

3 years ago

On the planet Tott, there are 7 rews to every 6 hopts. If farmer Boondin has 40 hopts on her frenk farm, how many rews are on th

Anestetic [448]

Answer:

uwuu

Step-by-step explanation:

ok the reason y iput uwu because uwu

4 0

3 years ago

Read 2 more answers

Use the following graph to evaluate f’(-5) and f’(-1).

Rzqust [24]

Answer:

Bonsoir,

f'(-5)=-4/3

f'(-1) =3/4

Step-by-step explanation:

f'(-5) = ?

2 points : (-6,9) and (-3,5)

f'(-5)=(9-5)/(-6-(-3))=-4/3

f'(-1) = ?

2 points : (-3,5) and (1,8)

f'(-1)=(5-8)/(-3-1)=3/4

The lines are perpendicular

8 0

3 years ago

Compute 2/3 x 1/3 + 1/3 (3 + 1/3) and express your answer as a mixed number. (Note that 3 1/3 should be read as a mixed number).

Dominik [7]

Answer:

1 1/3

Step-by-step explanation:

First, distribute the parenthesis.

Second, multiply the fractions.

Third, add the 2 values together to get your answer in improper form.

Lastly, turn the improper fraction into mixed form.

4 0

3 years ago