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3 years ago

Plants, algae, and certain microbes harness what kind of energy to produce their own nutrients using photosynthesis?

Biology

2 answers:

d1i1m1o1n [39]3 years ago

6 0

Answer:

Light energy from the sun.

Explanation:

Algae, plants and some bacteria such as cyanobacteria uses light energy from the sun, carbon dioxide and water to make organic molecules (sugars) to produce energy for growth. The by-product of this process in plants is oxygen and water vapour, released using the stomata (tiny openings in leaves).

Fynjy0 [20]3 years ago

4 0

Answer:

The answer is Solar Energy

Explanation:

Photosynthesis is the process that takes place in plants, algae and in some microbes, in which they take advantage of the light coming from the sun to convert it into chemical energy useful for the basic functions of the plant, such as nutrition, development and growth.

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3) What is the smallest unit that can carry on all functions of life? please help

nadya68 [22]

Answer:

cells

Explanation:

cells are the smallest unit that can carry life

6 0

3 years ago

Which of the following ancillary or supportive criteria is addressed in this statement: Infants who are put to bed prone less th

ZanzabumX [31]

Answer:

The answer is D- Dose-response relationship

Explanation:

A dose-response relationship is an association between dose and incidence in which an increasing level of exposure will either lead to an increase or decrease of an incident or outcome. For instance, in the scenario given the dose or exposure will be the time the infants are put to bed prone while the response is the level of incidence of SIDS (Sudden Infant Death Syndrome).

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3 years ago

Which is the definition of taxonomy

cricket20 [7]

Taxonomy is the branch of science that concerns labeling and classifying living things into more manageable groups. This helps scientists better understand certain species and their connections to other species.

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3 years ago

Why are saprotrophs so important to a marine food web?

Darina [25.2K]

Answer:

They break down dead organisms and recycle nutrients. They directly help to maintain the population sizes of different predators. They primarily eliminate toxins from the water that can harm phytoplankton.

Explanation:

Hope it helps I found it on brainly

5 0

4 years ago

Read 2 more answers

Cystic fibrosis (CF) is one of most common recessive disorders among Caucasians it affects 1 in 1,700 newborns. What is the expe

Phantasy [73]

Answer: The expected frequency of carriers is P(Aa)=0.046.

The proportion of childs with CF is P(aa)=0.024.

25% of having a child with CF (aa).

Explanation:

Hardy-Weinberg's principle states that in a large enough population, in which mating occurs randomly and which is not subject to mutation, selection or migration, gene and genotype frequencies remain constant from one generation to the next one, once a state of equilibrium has been reached which in autosomal loci is reached after one generation. So, a population is said to be in balance when the alleles in polymorphic systems maintain their frequency in the population over generations.

Given the gene allele frequencies in the gene pool of a population, it is possible to calculate the expected frequencies of the progeny's genotypes and phenotypes. <u>If P = percentage of the allele A (dominant) and q = percentage of the allele a (recessive)</u>, the checkerboard method can be used to produce all possible random combinations of these gametes.

Note that p + q = 1, that is, the percentages of gametes A and a must equal 100% to include all gametes in the gene pool.

The genotypic frequencies added together should also equal 1 or 100%, and all the equations can be summarized as follows:

$p+q=1\\(p+q)^{2} = p^{2} +2pq+q^{2} = 1\\P(AA)=p^{2} \\P(aa)=q^{2} \\P(Aa)=2pq1$

So, there are 1700 individuals and only one is affected. Since it is a recessive disorder, the genotype of that individual must be aa. So the genotypic frequency of aa is 1/1700=0.000588.

Then, $P(aa)=q^{2}=0.000588$ . And with that we can calculate the value of q,

$P(a)=q=\sqrt{0.000588}=0.024$

And since we know that p+q=1, we can find out the value of p.

$p+0.024=1\\1-0.024=p\\p=0.976$

Next, we find out the genotypic frequency of the genotype AA:

$P(A)=p=0.976\\P(AA)=p^{2} = 0.976^{2}=0.95$

Now, we can find out the genotypic frequency of the genotype Aa:

$P(Aa)=2pq=2 x 0.976 x 0.024 = 0.046$

Notice than:

$p^{2} + 2pq + q^{2} = 1\\x^{2} 0.976^{2} + 2 x 0.976 x 0.024 + 0.024^{2} = 1$

Then, the expected frequency of carriers is P(Aa)=0.046

The proportion of childs with CF is P(aa)=0.024

If two parents are carriers, then their genotypes are Aa.

Gametes produced by them can only have one allele of the gene. So they can either produce A gametes, or a gametes.

In the punnett square, we can see that there genotypic ratio is 2:1:1 and the phenotypic ratio is 3:1. So, there is a probability of 25% of having an unaffected child, with both normal alleles (AA); 50% of having a carrier child (Aa) and 25% (0.25) of having a child with CF (aa).

5 0

3 years ago