I am going with x-rays; it is the most visible to the naked eye out of all the choices.
Answer:
Zero (0)
Explanation:
According to the given information the genotype of the woman with blood type "AB" would by I^AI^B. The genotype of the man with blood type O would be "ii". Here, the alleles I^A and I^B are dominant over the allele "i".
A cross between parents with genotype I^AI^B and ii would give 50% of children with I^Ai genotype and 50% of children with I^Bi genotype. The children with "I^Ai genotype" would have blood type "A" and the children with I^Bi genotype would have blood type "B". This couple is never likely to have any child with blood type "O" since the mother does not carry allele "i".
Cross: I^AI^B x ii = 1/2 I^Ai : 1/2 I^Bi
Answer: d). UAG
Explanation: During translation, DNA sequence is first of all copied into an mRNA in a process known as transcription. This is the first step in protein synthesis. The mRNA is used as a template in protein synthesis. The genetic information encoded in an mRNA are in form of codons. A Codon is a three nucleotide sequence that codes for a specific amino acid. These codons are recognized by anticodons in a tRNA molecule. An anticodon is a three-base sequence on the tRNA through which tRNA base pair with mRNA.
From the DNA sequence above, 3'TAG will first be transcribed into an mRNA sequence AUC, then the anticodon on the tRNA will be UAG. The mRNA codon-tRNA anticodon base pairing follows the Watson and Crick base pairing in which Adenine pairs with Uracil and Cytosine pairs with Guanine.
