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bekas [8.4K]
3 years ago
13

10 increased by what percent is 30

Mathematics
2 answers:
ELEN [110]3 years ago
6 0
<span>10 increased by x%

10+x\%\cdot 10=30\\\\ 10+0.01x \cdot 10=30\\\\ 0,1x=20\ |*10 \\\\x=200

x% = 200%</span>
inysia [295]3 years ago
3 0
It is a 200 percent increase because it increases by 20, which is 200% of or 2 times 10.
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8. The graph of a horizontal line is a function. True False
11111nata11111 [884]

Answer:

It is not due to the fact it has no variable

7 0
3 years ago
A laboratory scale is known to have a standard deviation (sigma) or 0.001 g in repeated weighings. Scale readings in repeated we
weqwewe [10]

Answer:

99% confidence interval for the given specimen is [3.4125 , 3.4155].

Step-by-step explanation:

We are given that a laboratory scale is known to have a standard deviation (sigma) or 0.001 g in repeated weighing. Scale readings in repeated weighing are Normally distributed with mean equal to the true weight of the specimen.

Three weighing of a specimen on this scale give 3.412, 3.416, and 3.414 g.

Firstly, the pivotal quantity for 99% confidence interval for the true mean specimen is given by;

        P.Q. = \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \bar X = sample mean weighing of specimen = \frac{3.412+3.416+3.414}{3} = 3.414 g

            \sigma = population standard deviation = 0.001 g

            n = sample of specimen = 3

            \mu = population mean

<em>Here for constructing 99% confidence interval we have used z statistics because we know about population standard deviation (sigma).</em>

So, 99% confidence interval for the population​ mean, \mu is ;

P(-2.5758 < N(0,1) < 2.5758) = 0.99  {As the critical value of z at 0.5% level

                                                            of significance are -2.5758 & 2.5758}

P(-2.5758 < \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } < 2.5758) = 0.99

P( -2.5758 \times {\frac{\sigma}{\sqrt{n} } } < {\bar X - \mu} < 2.5758 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.99

P( \bar X-2.5758 \times {\frac{\sigma}{\sqrt{n} } } < \mu < \bar X+2.5758 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.99

<u>99% confidence interval for</u> \mu = [ \bar X-2.5758 \times {\frac{\sigma}{\sqrt{n} } } , \bar X+2.5758 \times {\frac{\sigma}{\sqrt{n} } } ]

                                             = [ 3.414-2.5758 \times {\frac{0.001}{\sqrt{3} } } , 3.414+2.5758 \times {\frac{0.001}{\sqrt{3} } } ]

                                             = [3.4125 , 3.4155]

Therefore, 99% confidence interval for this specimen is [3.4125 , 3.4155].

6 0
3 years ago
Help me with this please.​
horrorfan [7]

Answer:

1=point

2=line

3=line

4=line segment

5=ray

6=plane

7=plane

Step-by-step explanation:

4 0
3 years ago
Need the formula for 8% of 575
Nitella [24]
The formula of that is 24
7 0
3 years ago
Read 2 more answers
How many table spoons of vanilla will she use? Plss provide how you got the answer
Ksivusya [100]
Hi!
In one batch she uses 3/4 teaspoon of vanilla
therefore in 5 batch she uses 5*3/4=15/4 teaspoons of vanilla.
as it is given that 3 teaspoons=1 tablespoon
the amount of vanilla used for 5 batches =(15/4)/3=(15/4)*1/3=5/4==1.25 tablespoons.

All the best.
4 0
3 years ago
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