Answer:
a) weight of the car = 2816,1 lbs
b) 2773 lbs
Step-by-step explanation:
The equilibrium force is 490 lbs. That force keep the car at rest, then
∑ Fy = 0 and ∑Fx = 0
Forces acting on the car:
The external force 490 lbs
weight of the car uknown
Normal force
sin∠10° = 0,174
cos∠10° = 0.985
∑Fx = 0 mg*sin10°- 490 = 0 ∑Fy = 0 mg*cos10° - N = 0
mg*0,174= 490
mg = 490 / 0,174
mg = 2816,1 lbs
weight of the car = 2816,1 lbs
The Normal force
mg*cos10° - N = 0 2816,1 * 0,985 = N
N = 2773 lbs
Then equal force in magnitude and in opposite direction will car exets on the driveway
Answer:
The common difference is same = d = -9
Therefore, the data represent a linear function.
Step-by-step explanation:
Given the table
x y
1 4
2 -5
3 -14
4 -23
5 -32
Finding the common difference between all the adjacent terms of y-values
d = -5 - 4 = -6,
d = -14 - (-5) = -14+5 = -9
d = -23 - (-14) = -23 + 14 = -9
d = -32 - (-23) = -32 + 23 = -9
It is clear that the common difference between all the adjacent terms is same.
Thus,
d = -9
We know that when y varies directly with x, the function is a linear function.
Here, it is clear that each x value varies 1 unit, and each y value varies -9 units.
i.e. The common difference is same = d = -9
Therefore, the data represent a linear function.
Answer:
t=(v-u)/a
Step-by-step explanation:
The equation we start with is v=u+at and we need to isolate t.
First subtract u from both sides
v-u=at
Now just divide both sides by a
(v-u)/a=t or t=(v-u)/a
Answer:
90 I am guessing. if it's like a square or rectangle
Answer:
sorry i cant cick out plz dont report my moused died plzzzzzz
Step-by-step explanation: