Answer:
8.7 cm
Step-by-step explanation:
The question is a 2-two-step Pythagoras theorem. (c^2 = a^2 + b^2)
Consider as such, If I were to draw a diagonal line along the base of the cube what is the length of the diagonal line. To find out that we use the theorem. We can substitute a for 5 and b for 5 as well. So
a^2 +b^2 = c^2
5^2 + 5^2 = c^2
25 + 25 = c^2
√50 = c
Then since the line side of the cube is on a 3d angle we need to do the same process again but now using the imaginary diagonal line that we just calculated and the height (5).
a^2 +b^2 = c^2
√50^2 + 5^2 = c^2
50 + 25 = c^2
√75 = c
c = 8.6602...
<em>when rounded to 1 d.p.</em>
c = 8.7
Line AB is 8.7 cm long.
I can’t see anything on the thing bro
Answer:
28 units²
Step-by-step explanation:
Assume that your net has the dimensions shown below.
Its area is
2 yellow rectangles = 2(4 × 2) = 2 × 8 = 16 units²
2 grey rectangles = 2(4 × 1) = 2 × 4 = 8 units²
2 green rectangles = 2(2 × 1) = 2 × 2 = <u> 4 units²</u>
TOTAL = 28 units²
The prism's surface area is 28 units².