Answer:
Acceleration=3.95
Explanation:Use the formula a=m/f
a=128.6/32.5
a=3.95
Complete Question:
Football player A has a mass of 110 kg, and he is running down the field with a velocity of 2 m/s. Football player B has a mass of 120 kg and is stationary. What is the total momentum after the collision?
Answer:
Total momentum = 220 Kgm/s.
Explanation:
<u>Given the following data;</u>
For footballer A
Mass, M1 = 110kg
Velocity, V1 = 2m/s
For footballer B
Mass, M1 = 120kg
Velocity, V1 = 0m/s since he's stationary.
To find the total momentum;
Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.
Mathematically, momentum is given by the formula;
a. To find the momentum of A;

Momentum A = 220 Kgm/s.
b. To find the momentum of B;

Momentum B = 0 Kgm/s.
c. To find the total momentum of the two persons;
Substituting into the equation, we have;

<em>Total momentum = 220 Kgm/s. </em>
Answer:
A book on a table before it falls.
A yoyo before it is released.
A raised weight.
Explanation:
These are all examples of potential energy. So I hope you can find something that is comparable from the lab.
Answer:
Explanation:
Threshold frequency = 4.17 x 10¹⁴ Hz .
minimum energy required = hν where h is plank's constant and ν is frequency .
E = 6.6 x 10⁻³⁴ x 4.17 x 10¹⁴
= 27.52 x 10⁻²⁰ J .
wavelength of radiation falling = 245 x 10⁻⁹ m
Energy of this radiation = hc / λ
c is velocity of light and λ is wavelength of radiation .
= 6.6 x 10⁻³⁴ x 3 x 10⁸ / 245 x 10⁻⁹
= .08081 x 10⁻¹⁷ J
= 80.81 x 10⁻²⁰ J
kinetic energy of electrons ejected = energy of falling radiation - threshold energy
= 80.81 x 10⁻²⁰ - 27.52 x 10⁻²⁰
= 53.29 x 10⁻²⁰ J .