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MAVERICK [17]
3 years ago
15

Anne should use a to transfer electric energy into motion. She should also use a to start and stop the flow of current.

Physics
1 answer:
tester [92]3 years ago
4 0
<span>Anne should use a MOTOR to transfer electric energy into motion. She should also use a SWITCH to start and stop the flow of current.</span>
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How fast is a cat that runs 50 meters in 10 seconds?
saw5 [17]

Answer:

50 m in 10 sec….divide 50 by 10 to convert to metres per second = 5 m/s. Then multiply by 3.6 (3600 seconds in an hour divided by 1000) to convert to kilometres per hour =18 m/s. To convert to mph divide by 1.609 =11.18 mph.

Explanation:

5 0
3 years ago
Read 2 more answers
A 250 mL sample of nitrogen(N2) has a pressure of 745 mm Hg at 30 C.What is the mass of nitrogen?
Lera25 [3.4K]
We assume that nitrogen gas sample here is an ideal gas. So that, we can use the ideal gas equation which is expressed as follows:

PV = nRT

First, we calculate the number of moles from the equation above. Then, use molar mass to calculate mass.

n = PV/RT
n = (745/760) (0.250) / 0.08206 (30+273.15)
n = 0.01 mol 

m = 0.01 ( 28) = 0.28 g
3 0
3 years ago
A meter stick is found to balance at the 49.7-cm mark when placed on a fulcrum. When a 65.5-gram mass is attached at the 21.0-cm
Gnesinka [82]

Answer:

113.53 g

Explanation:

Please see attached photo for explanation.

In the attached photo, M is the mass of the meter stick.

The value of M can be obtained as shown below:

Clockwise moment = M × 10.5

Anticlockwise moment = 65.5 × 18.2

Anticlockwise moment = Clockwise moment

65.5 × 18.2 = M × 10.5

1192.1 = M × 10.5

Divide both side by 10.5

M = 1192.1 / 10.5

M = 113.53 g

Thus, the mass of the meter stick is 113.53 g

7 0
2 years ago
An observer at the top of a 462-ft cliff measures the angle of depression from the top of the cliff to a point on the ground to
Lana71 [14]

complete question:

An observer at the top of a 462-ft cliff measures the angle of depression from the top of the cliff to a point on the ground to be 5°. What is the distance from the base of the cliff to the point on the ground? Round to the nearest foot

Answer:

a ≈  5281 ft

Explanation:

The observer at the top of a 462 ft cliff  measures the angle of depression from the top of the cliff to a point on the ground to be 5°.

The angle of depression form the top of the cliff = 5°

The 5° is outside the triangle formed . To find the angle in the triangle we have to subtract 5° from 90°.  90° - 5° = 85° Note sum of an angle on a right angle is 90°.  

using SOHCAHTOA  principle we can solve for the distance from the base of the cliff to the point on the ground(a)

tan  85° = opposite / adjacent

tan 85°  = a / 462

cross multiply

462 × tan 85° = a

a = 11.4300523 × 462

a =  5280.66  ft

a ≈  5281 ft

5 0
3 years ago
Which formula can be used to find the angle of the resultant vector has
nata0808 [166]
The diagram shows components that have been added together to form Rx and Ry. Rx and Ry are the components of the resultant vector.
Which formula can be used to find the angle of the resultant vector?
the answer is C
C.  tan0= Ry/Rx
5 0
3 years ago
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