Question

A football is thrown at an angle of 44◦ above the horizontal. Assume the ball is throw and received at the same height. To throw a 55.7 m pass, what must be the initial speed of the ball? The acceleration due to gravity is 9.8 m/s 2 . Answer in units of m/s.

Answer 1

Answer:

The initial speed of the ball is 23.3 m/s.

Explanation:

Given that,

Angle = 44°

Range = 55.7 m

We need to calculate the initial speed of the ball

Using formula of range

$R=\dfrac{u^2\sin2\theta}{g}$

Where. u = initial velocity

r = range

g = acceleration due to gravity

Put the value into the formula

$55.7=\dfrac{u^2\sin2\times44}{9.8}$

$u^2=\dfrac{55.7\times9.8}{\sin88}$

$u=\sqrt{\dfrac{55.7\times9.8}{\sin88}}$

$u=23.3\ m/s$

Hence, The initial speed of the ball is 23.3 m/s.