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exis [7]
2 years ago
10

A football is thrown at an angle of 44◦ above the horizontal. Assume the ball is throw and received at the same height. To throw

a 55.7 m pass, what must be the initial speed of the ball? The acceleration due to gravity is 9.8 m/s 2 . Answer in units of m/s.
Physics
1 answer:
aleksley [76]2 years ago
4 0

Answer:

The initial speed of the ball is 23.3 m/s.

Explanation:

Given that,

Angle = 44°

Range = 55.7 m

We need to calculate the initial speed of the ball

Using formula of range

R=\dfrac{u^2\sin2\theta}{g}

Where. u = initial velocity

r = range

g = acceleration due to gravity

Put the value into the formula

55.7=\dfrac{u^2\sin2\times44}{9.8}

u^2=\dfrac{55.7\times9.8}{\sin88}

u=\sqrt{\dfrac{55.7\times9.8}{\sin88}}

u=23.3\ m/s

Hence, The initial speed of the ball is 23.3 m/s.

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natta225 [31]

Answer: the one spinnin

Explanation:

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2 years ago
Compare and contrast the average kinetic energy of 0.5 L of coffee at 34ÁC,
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Compared to coffee at room temperature, the molecules of the coffee at 34°C will be moving faster and colliding with one another more frequently.
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3 years ago
A 1200 Kg car rounds a corner of radius r = 45m. If the coefficient of static friction between the ties and the road is us = 0.8
Vaselesa [24]

Answer:

The greatest speed of the car is 19.36m/s

Explanation:

The maximum speed the car will attain without skidding is given by:

F= uN = umg ...eq1

But F = mv^2/r

mv^2/r = umg

Dividing both sides by m, leaves you with:

V= Sqrt(ugr)

Where u = coefficient of static friction

g = acceleration due to gravity

r = raduis

Given:

U = 0.82

r=0.82

g= 9.8m/s

V = Sqrt(0.82 × 9.8 × 45)

V = Sqrt(374.85)

V = 19.36m/s

5 0
3 years ago
A certain nuclear power plant is capable of producing 1.2×10^9 W of electric power. During operation of the reactor, mass is con
alukav5142 [94]

Answer:

0.00016 kg

Explanation:  

Given:

Power = P = 1.2 × 10⁹ Watts

Power =  work done / Time

efficiency = 0.30

Input power = 1.2 × 10⁹ / 0.30 =  4  × 10⁹ W

Energy =  4  × 10⁹ x 60 x 60 = 1.44 x 10¹³ joules

E = m c² , where c is the speed of light and m is the mass.

⇒ mass = m = E / c²  = (1.44 x 10¹³) / (3 × 10⁸ )²

                                   = 0.00016 kg

6 0
3 years ago
Question #6a) You were told to assume that the ball bounced to a height of 1.2 m and that the distance between the bounces measu
Inessa [10]

Answer:

Explanation:

In the problem they give the case of a ball that bounces on the vertical axis the height is getting smaller, on the x axis it is the same distance all the time.

Questions about the aspect of the x-axis

- Since the distance traveled between the rebounds is the same, the speed must be the same or constant throughout the entire journey.

- Since the distance and speed are equal, the time between rebounds is the same

- There can be no acceleration because the bounce gap should change, the acceleration is zero all the time

Questions about the Y axis

- The vertical speed of the first boat would be the greatest of all, so it has the highest height

b) Evidence or not Evidence

1  evidence, because the graphs are different, one is a straight line and he gives a parable

2 no evidence, nothing involved on the x axis

3  no evidence, the acceleration on the y axis is independent of the acceleration on the x axis

4  no evidence, the time that is cast is the only change that is the same for both movements

5  evidence, the fact that no mixture of components is found allows the variable to be separated into different equations

6  no evidence, says nothing about the x-axis

4 0
3 years ago
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