The complete question is as follows: The equilibrium constant, Kp, for the following reaction is 10.5 at 350 K: 2CH2Cl2(g) CH4(g) + CCl4(g) Calculate the equilibrium partial pressures of all species when CH2Cl2(g) is introduced into an evacuated flask at a pressure of 0.968 atm at 350 K. PCH2Cl2 = atm PCH4 = atm PCCl4 = atm
Answer: The equilibrium partial pressures of all species, that is,
,
and
is 0.420 atm, 0.420 atm and 0.128 atm.
Explanation:
For the given reaction equation, the initial and equilibrium concentration of involved species is as follows.
Initial: 0.968 atm 0 0
Equilibrium: (0.968 - 2x) x x
Now,
for this reaction is as follows.


Thus, we can conclude that the equilibrium partial pressures of all species, that is,
,
and
is 0.420 atm, 0.420 atm and 0.128 atm.
HCl + NaOH -> NaCl + H2O
reactants: hydrochloric acid HCl
sodium hydroxide NaOh
products: sodium chloride (table salt) NaCl
dihydrogen monoxide (water)
H2O
From electronic configuration valence electron of Nitrogen is 5, oxygen 6x2 which 12 since it involve two molecules , that of is frulorine is 7, and that No2F is 24 which is gotten form adding (5,12,7 ).All resonance structure are as follows
F
.. I ..
: O : N :O:
..
OR : F:
I
N .. : F:
/ \ or I
.. .. N
:O : :O: / / \\
/ / \\
:O : : O:
Answer:
Explanatio
NCO2= 0, 248 /44= 0 ,005636
VCO2= 0,005636* 22,4= 0 ,126254545