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Elenna [48]
3 years ago
5

Draw all resonance structures for the nitryl fluoride molecule, no2f.

Chemistry
1 answer:
denis-greek [22]3 years ago
7 0
From  electronic  configuration valence electron of  Nitrogen is 5,  oxygen  6x2  which 12 since it  involve  two  molecules ,  that of is frulorine is  7, and  that No2F is 24  which  is  gotten  form  adding (5,12,7  ).All  resonance structure  are  as  follows
       F
 ..    I    ..
: O : N :O: 
 
              ..
     OR  : F:
              I                             

             N                                                  ..                                                                                                                                    : F:

          /         \                        or                   I

   ..                 ..                                               N

:O  :            :O:                                       / /        \\
                                                            / /               \\
                                                         :O :            :  O:
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what is the proper name for the following alkyl side group where the main carbon chain is denoted with a squiggly line?
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The proper name for the following alkyl side group where the main carbon chain is denoted with a squiggly line is isopropyl.

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what is an alkyl group? Alkyl group is shaped through putting off a hydrogen atom from the molecule of alkane. Alkanes are quite regularly represented as R-H and here R stands for alkyl group. the overall method of the alkyl organization is CₙH₂ₙ₊₁. The smallest alkyl organization is CH3 referred to as methyl.

Learn more about alkyl group here:- brainly.com/question/14272539

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4 0
1 year ago
What functions of cells can be affected by a mutation?
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6 0
3 years ago
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4 0
2 years ago
Read 2 more answers
How many moles of N2 in 57.1 g of N2?
SpyIntel [72]

We are given –

  • Mass of \bf N_2 is 57.1 g and we are asked to find number of moles present in 57.1 g of \bf N_2

\qquad\pink{\bf\longrightarrow  { Molar \:mass \:of \: N_2:-}  }

\qquad\bf  \twoheadrightarrow 14\times 2

\qquad\bf \twoheadrightarrow   28

\qquad____________________

Now,Let's calculate the number of moles present in 57.1 g of \bf N_2

\qquad\purple{\bf\longrightarrow  { No \:of \:moles = \dfrac{Given \:mass}{Molar\: mass}}}

\qquad\bf   \twoheadrightarrow \dfrac{57.1}{28}

\qquad\bf  \twoheadrightarrow 2.04\: moles

__________________________________

7 0
2 years ago
How many mL of 0.013 M potassium hydroxide are required to reach the equivalence point in the titration of 75 mL 0.166 M hydrocy
umka21 [38]

Answer:

957.7mL

Explanation:

Using the formula below;

CaVa = CbVb

Where;

Ca = concentration of acid (M)

Va = volume of acid (mL)

Cb = concentration of base (M)

Vb = volume of base (mL)

According to the information provided in this question:

Ca = 0.166 M

Cb = 0.013 M

Va = 75mL

Vb = ?

Using CaVa = CbVb

0.166 × 75 = 0.013 × Vb

12.45 = 0.013Vb

Vb =12.45/0.013

Vb = 957.7mL

6 0
2 years ago
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