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stira [4]
3 years ago
12

For the reaction 2N 2O(g) ⇌ O 2(g) + 2N 2(g), what happens to the equilibrium position if the pressure increases?

Chemistry
1 answer:
scZoUnD [109]3 years ago
5 0

Answer:

Equilibrium will shift in forward direction.

Explanation:

According to Le Chatelier's Principle, the change in any state of the equilibrium say temperature, volume, pressure, or the concentration, the equilibrium will oppose these changes and will shift in such a way that the effect cause must be nullified.

Effect of the change in the pressure :

If the pressure is increased , the equilibrium of the reaction is disturbed , so , the reaction will move in order to decrease the pressure.

The molecules of gas are responsible for the pressure and thus to nullify this effect or to decrease the pressure, the equilibrium will shift in a direction where there are less number of gaseous molecules.

For the reaction given ,

2N₂O (g) ⇄ O₂(g) + 2N₂(g)

<u>The number of gaseous molecules in the product (2) is less than the reactant (2 + 1), so the equilibrium will shift in forward direction.</u>

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How many moles of mercury are equivalent to 3.46 x 1023 atoms?
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Answer:

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2 years ago
An aqueous CsCl solution is 8.00 wt% CsCl and has a density of 1.0643 g/mL at 20°C. What is the boiling point of this solution?
umka2103 [35]

<u>Answer:</u> The boiling point of solution is 100.53

<u>Explanation:</u>

We are given:

8.00 wt % of CsCl

This means that 8.00 grams of CsCl is present in 100 grams of solution

Mass of solvent = (100 - 8) g = 92 grams

The equation used to calculate elevation in boiling point follows:

\Delta T_b=\text{Boiling point of solution}-\text{Boiling point of pure solution}

To calculate the elevation in boiling point, we use the equation:

\Delta T_b=iK_bm

Or,

\text{Boiling point of solution}-\text{Boiling point of pure solution}=i\times K_b\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}

where,

Boiling point of pure solution = 100°C

i = Vant hoff factor = 2 (For CsCl)

K_b = molal boiling point elevation constant = 0.51°C/m

m_{solute} = Given mass of solute (CsCl) = 8.00 g

M_{solute} = Molar mass of solute (CsCl) = 168.4  g/mol

W_{solvent} = Mass of solvent (water) = 92 g

Putting values in above equation, we get:

\text{Boiling point of solution}-100=2\times 0.51^oC/m\times \frac{8.00\times 1000}{168.4g/mol\times 92}\\\\\text{Boiling point of solution}=100.53^oC

Hence, the boiling point of solution is 100.53

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3 years ago
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Answer:

He was the first scientist to observe and describe bacteria and protozoa by looking at a drop of water from a pound under a microscope. He also was the one to build the first compound microscope.

Hope this helps :)

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Explanation:

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3 years ago
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