Determine whether the parabola x = y2 + 3 opens up, down, left, or right
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Answer:
Step-by-step explanation:
the system is : 3x + y + 2 = 0.......(1)
2x - y + 3 = 0......(2)
x+ py - 3 = 0......(3)
(1)+(2) : 3x+y+2 +2x-y+3 =0
5x+5 =0
so : x = -1
put x = -1 in equation (2) : 2(-1)-y+3 = 0
so : y = 1
the intersection point is A(-1 ; 1)
put x = -1 and y = 1 in equation (3) : -1+p(1)-3 =0 so : p = 4
sketch the line :3x + y + 2 = 0 and 2x - y + 3 = 0 and x+ 4y - 3 = 0
y = -3x-2 ...(color red) and y=2x+3....(color blue) and y = -1/4x +3/4...(color purple)
