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Kitty [74]
3 years ago
13

Line BD is tangent to circle O at C, Arch AEC = 299, and ACE = 93. Find Angle DCE.

Mathematics
1 answer:
VladimirAG [237]3 years ago
7 0
In triangle ACE,
we know C=93,E can be calulated by using arch angle AEC...what ever that is....,using this we get  A=180-(E+93)

So, by alternate segment theorem, DCE= A.

thats all i can say.
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Add the two expressions.<br> 2x + 6 and 6.2 - 1<br> Enter your answer in the box.
madam [21]

Answer:

8x + 5

Step-by-step explanation:

By adding

2x + 6 + 6x -1

8x + 5

8 0
3 years ago
What is the length of ST? Please explain your answer
Aliun [14]
We know that

If a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment. (Intersecting Secant-Tangent Theorem)

so

ST²=RT*QT

RT=7 in

QT=23+7-----> 30 in

ST²=7*30-----> 210

ST=√210-----> 14.49 in


the answer is

RT=14.49 in

4 0
3 years ago
Are 6:24 and 9:45 ratios equivalent
scoundrel [369]
No. If you do 6+1/3 and 24+1/3 it is not equal.
8 0
2 years ago
You are selling lemonade for $1.50, a bag of kettle corn for $3, and a hot dog for $2.50 at a fair. Write and simplify an expres
kozerog [31]

Answer:

1.5p + 3p + 2.5p

Step-by-step explanation:

This expression, 1.5p + 3p + 2.5p, will represent the amount of money received when p people buy one of each food item.

Since the price of each is the coefficient for p, this will represent how much money will be gained from each food item. All 3 terms will be added together to represent the total amount of money gained from selling all 3 items.

4 0
3 years ago
Sixty percent of the students at a certain school wear neither a ring nor a necklace. Twenty percent wear a ring and 30 percent
Reptile [31]

Answer:

0.4

Step-by-step explanation:

Given

60 % wear neither ring nor a necklace

20 % wear a ring

30 % wear necklace

This question can be Solved by using Venn diagram

If one person is choosen randomly  among the given student the probability that this student is wearing a ring or necklace is

P\left ( wear \ ring\ or \ necklace )+P\left ( neither\ ring\ or\ necklace)=1

P\left ( wear \ ring\ or\ necklace )=1-0.6=0.4

The sum of probabilty is equal to 1 because it completes the set

Therefore the required probabilty is 0.4

7 0
3 years ago
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