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Kitty [74]
3 years ago
13

Line BD is tangent to circle O at C, Arch AEC = 299, and ACE = 93. Find Angle DCE.

Mathematics
1 answer:
VladimirAG [237]3 years ago
7 0
In triangle ACE,
we know C=93,E can be calulated by using arch angle AEC...what ever that is....,using this we get  A=180-(E+93)

So, by alternate segment theorem, DCE= A.

thats all i can say.
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Answer:

  AE = CE = 23; BE = DE = 20

Step-by-step explanation:

Put the values of the variables in their place and do the arithmetic.

  AE = 2u+5 = 2(9) +5 = 23

  BE = 6v-1 = 6(3.5) -1 = 20

  CE = 3u-4 = 3(9) -4 = 23

  DE = 8v-8 = 8(3.5) -8 = 20

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The incorrect work of a student to solve an equation 2(y + 6) = 4y is shown below.
Lina20 [59]

Answer:

<h3>⇒ A. 2 should be distributed as 2y + 12, y = 6</h3>

Step-by-step explanation:

Here are the steps to solve this equation:

<u>Given:</u>

First step: 2(y+6)-4y

Use the distributive property.

<u>Distributive property:</u>

<h3>⇒ A(B+C)=AB+AC</h3>

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2*y=2y

2*6=12

2y+12

Isolate the term of y from one side of the equations.

2y+12=4y

Subtract by 12 from both sides.

2y+12-12=4y-12

Solve.

2y=4y-12

Then, you subtract by 4y from both sides.

2y-4y=4y-12-4y

Solve.

2y-4y=-2y

-2y=-12

Divide by -2 from both sides.

\sf{\dfrac{-2y}{-2}=\dfrac{-12}{-2}}

Solve.

Divide the numbers from left to right.

<u>Solutions:</u>

-12/-2=6

\Longrightarrow: \boxed{\sf{y=6}}

  • <u>Therefore, the correct answer is A. "2 should be distributed as 2y+12, y=6".</u>

I hope this helps. Let me know if you have any questions.

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Answer:

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Step-by-step explanation:

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