Answer:
first 1/4, second 0.4, third 0.5
Answer:
Step-by-step explanation:
umm like 2.8 i think
we know that the cos(θ) is -(3/5), however θ is in the II Quadrant, where the cosine is negative whilst the sine is positive, meaning the fraction is really (-3)/5, so
![cos(\theta )=\cfrac{\stackrel{adjacent}{-3}}{\underset{hypotenuse}{5}}\qquad \qquad \textit{let's find the \underline{opposite side}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases}](https://tex.z-dn.net/?f=cos%28%5Ctheta%20%29%3D%5Ccfrac%7B%5Cstackrel%7Badjacent%7D%7B-3%7D%7D%7B%5Cunderset%7Bhypotenuse%7D%7B5%7D%7D%5Cqquad%20%5Cqquad%20%5Ctextit%7Blet%27s%20find%20the%20%5Cunderline%7Bopposite%20side%7D%7D%20%5C%5C%5C%5C%5C%5C%20%5Ctextit%7Busing%20the%20pythagorean%20theorem%7D%20%5C%5C%5C%5C%20c%5E2%3Da%5E2%2Bb%5E2%5Cimplies%20%5Csqrt%7Bc%5E2-a%5E2%7D%3Db%20%5Cqquad%20%5Cbegin%7Bcases%7D%20c%3Dhypotenuse%5C%5C%20a%3Dadjacent%5C%5C%20b%3Dopposite%5C%5C%20%5Cend%7Bcases%7D)
![\pm\sqrt{5^2-(-3)^2}=b\implies \pm\sqrt{25-9}=b\implies \pm 4=b\implies \stackrel{II~Quadrant}{+4=b} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill csc(\theta )=\cfrac{\stackrel{hypotenuse}{5}}{\underset{opposite}{4}}~\hfill](https://tex.z-dn.net/?f=%5Cpm%5Csqrt%7B5%5E2-%28-3%29%5E2%7D%3Db%5Cimplies%20%5Cpm%5Csqrt%7B25-9%7D%3Db%5Cimplies%20%5Cpm%204%3Db%5Cimplies%20%5Cstackrel%7BII~Quadrant%7D%7B%2B4%3Db%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20~%5Chfill%20csc%28%5Ctheta%20%29%3D%5Ccfrac%7B%5Cstackrel%7Bhypotenuse%7D%7B5%7D%7D%7B%5Cunderset%7Bopposite%7D%7B4%7D%7D~%5Chfill)
Answer:
910
Step-by-step explanation:
65×14=910
Answer:
{A and B are independent events}, P(A|B)=P(A)=0.16
Step-by-step explanation:
First of all we need to know when does two events become independent:
For the two events to be independent, P(A|B)=P(A) that is if condition on one does not effect the probability of other event.
Here, in our case the only option that satisfies the condition for the events to be independent is P(A|B)=P(A)=0.16.. Rest are not in accordance with the definition of independent events.