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2 years ago

The distance between the two points rounding to the nearest tenth (-8,-6) and (-3,-4)

Mathematics

1 answer:

Lesechka [4]2 years ago

3 0

Answer:

5.4

Step-by-step explanation:

To find the distance between two points, $(x_1,y_1)$ and $(x_2,y_2)$ , plug them into the following equation:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\d=\sqrt{(-3-(-8))^2+(-4-(-6))^2}$

Two negatives make a positive

$d=\sqrt{(-3+8)^2+(-4+6)^2}\\d=\sqrt{(5)^2+(2)^2}\\d=\sqrt{25+4}\\d=\sqrt{29}\\d=5.4$

Therefore, the distance between the two points rounded to the nearest tenth is 5.4.

I hope this helps!

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Solution to the problem

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$\mu =90 , \sigma =14$

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