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3 years ago

How do I solve x in a triangle

Mathematics

2 answers:

Andreas93 [3]3 years ago

6 0

How To Figure Out The Value Of x In A Triangle When The Angles Are Expressions (Solving Triangles)

57K views

A video I recommend to help explain/tell you how to solve x in a triangle

I'm giving you a video cuz I'm not very go at explaining

Sindrei [870]3 years ago

3 0

All three sides always add up to 360 so add the given measures and subtract it from 360 and that would give you your answer.

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Matias preformed an operation with 7.6 and a number. He ended up moving the decimal point in 7.6 two places to the left. Matias

olga2289 [7]

Answer:

Matias divided 7.6 by 10 raised to the power of -2.

Step-by-step explanation:

Given : Matias preformed an operation with 7.6 and a number. He ended up moving the decimal point in 7.6 two places to the left.

To find : Matias divided 7.6 by 10 raised to the power of ?

Solution :

Matias preformed an operation with 7.6 and a number.

He ended up moving the decimal point in 7.6 two places to the left we have to multiply it with 0.01

i.e. $7.6\times 0.01=\frac{7.6}{100}=0.076$

So, Matias divided 7.6 by 10 raised to the power of -2.

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3 years ago

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bearhunter [10]

Answer:

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natali 33 [55]

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3 years ago

A statistician selected a random sample of 125 observations from a population with a known standard deviation equal to 16 and co

serious [3.7K]

Answer:

Step-by-step explanation:

Given that a statistician selected a random sample of 125 observations from a population with a known standard deviation equal to 16 and computed a sample mean equal to 77

We can use Z critical values since population std deviation is known. Also sample size >30

We find std error of mean = $\frac{16}{\sqrt{125} } \\=1.4311$

Margin of error = Z critical value * 1.4311

Z critical values for 93% = 1.81

for 89% = 1.60

n Std error Z critical Conf interval

89%

125 1.4311 1.6 (74.71024 79.28976 )

93%

1.81 (74.409709 79.590291 )

We find that when confidence level increases interval width increses.

c) When sigma changes to 441, std error changes to $\frac{16}{\sqrt{441} } \\=0.7619$

So we get

n Std error Z critical Conf interval

89%

441 0.7619 1.6 (75.781 78.219 )

93%

1.81 (75.621 78.37904)

d) When n = 625, std error changes to 16/25 = 0.64

n Std error Z critical Conf interval

89%

441 0.64 1.6 (75.976 78.024 )

93%

1.81 (75.842 78.1584)

When sample size increases, confidence interval width decreases.

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3 years ago