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tiny-mole [99]
4 years ago
9

Max can make 1 greeting card in 5 minutes. How many greeting cards can he make in 30 minutes?

Mathematics
2 answers:
Debora [2.8K]4 years ago
5 0
Let's turn this into a rate,

1 greeting card/ 5 minutes

in order to get from 5 minutes to 30 minutes, we need to multiply both sides by 6

6 greeting cards/30 minutes

Anastasy [175]4 years ago
3 0

Answer:

He can make 6 greeting cards in 30 minutes.

Step-by-step explanation:

Given,

Max can make 1 greeting card in 5 minutes,

So, we can write,

5 minutes = 1 greeting card,

We have to find the number of cards for 30 minutes,

Multiply 6 on both sides,

30 minutes = 6 greeting cards,

Hence, he can make 6 greeting cards in 30 minutes.

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What is the area of the parallelogram shown?<br> 18 inches<br> 24 inches<br> Hurry up pls pls
LiRa [457]

Answer:

the answer is 432 inches

Step-by-step explanation:

A=bh

18·24=432

6 0
3 years ago
Read 2 more answers
Please help with 11c!?
Contact [7]

Answer:

"To the nearest year, it would be about 9 years"

Step-by-step explanation:

11c)

This is compound growth problem. It goes by the formula:

F=P(1+r)^t

Where

F is the future amount

P is the present (initial) amount

r is the rate of growth, in decimal

t is the time in years

Given,

P = 20,000

r = 8% = 8/100 = 0.08

F = double of initial amount = 2 * 20,000 = 40,000

We need to find t:

F=P(1+r)^t\\40,000=20,000(1+0.08)^t\\2=(1.08)^t

To solve exponentials, we can take Natural Log (Ln) of both sides:

2=(1.08)^t\\Ln(2)=Ln((1.08)^t)

Using the rule shown below we can simplify and solve:

Ln(a^b)=bLn(a)

We can write:

Ln(2)=Ln((1.08)^t)\\Ln(2)=tLn(1.08)\\t=\frac{Ln(2)}{Ln(1.08)}\\t=9.0064

To the nearest year, that would be about 9 years

5 0
3 years ago
Which of the following points could be the initial point of vector v if it has a magnitude of 10 an the terminal point (-1,5)?
Eddi Din [679]
Let the initial point of the vector be (x,y). Then the magnitude of the vector v can be written as:

|v|= \sqrt{ (-1-x)^{2} + (5-y)^{2} }

The magnitude of vecor v is given to be 10. So we can write:

10= \sqrt{ (-1-x)^{2} + (5-y)^{2} } \\ \\ 100=(-1-x)^{2} + (5-y)^{2}

Now from the given options, we have to check which one satisfies the above equation. That point will be the initial point of the vector. 

The point in option d, satisfies the equation.

100=(-1+7)^{2} +(5+3)^{2}  \\  \\ &#10;100=36+64 \\  \\ &#10;100=100

Thus, the answer to this question is option D
7 0
3 years ago
Write 500as a product of a prime number factors each factors must be greater than 1 and can have on 1 and its self as factors
zheka24 [161]
500 = 2 * 2 * 5 * 5 * 5
 

5 0
3 years ago
Solving the equation
liubo4ka [24]

Answer:

y = 5

Step-by-step explanation:

Step 1: Write equation

-(4y + 2) - (-3y - 6) = -1

Step 2: Solve for <em>y</em>

  1. Distribute: -4y - 2 + 3y + 6 = -1
  2. Combine like terms: -y + 4 = -1
  3. Subtract 4 on both sides: -y = -5
  4. Divide both sides by -1: y = 5

Step 3: Check

<em>Plug in y to verify it's a solution.</em>

-(4(5) + 2) - (-3(5) - 6) = -1

-(20 + 2) - (-15 - 6) = -1

-22 - (-21) = -1

-22 + 21 = -1

-1 = -1

7 0
3 years ago
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